Weight = 45 * 9.8 = 441 N
Answer:


Explanation:
The period of the comet is the time it takes to do a complete orbit:
T=1951-(-563)=2514 years
writen in seconds:

Since the eccentricity is greater than 0 but lower than 1 you can know that the trajectory is an ellipse.
Therefore, if the mass of the sun is aprox. 1.99e30 kg, and you assume it to be much larger than the mass of the comet, you can use Kepler's law of periods to calculate the semimajor axis:
![T^2=\frac{4\pi^2}{Gm_{sun}}a^3\\ a=\sqrt[3]{\frac{Gm_{sun}T^2}{4\pi^2} } \\a=1.50*10^{6}m](https://tex.z-dn.net/?f=T%5E2%3D%5Cfrac%7B4%5Cpi%5E2%7D%7BGm_%7Bsun%7D%7Da%5E3%5C%5C%20a%3D%5Csqrt%5B3%5D%7B%5Cfrac%7BGm_%7Bsun%7DT%5E2%7D%7B4%5Cpi%5E2%7D%20%7D%20%5C%5Ca%3D1.50%2A10%5E%7B6%7Dm)
Then, using the law of orbits, you can calculate the greatest distance from the sun, which is called aphelion:

In series with the circuit, so for it pass the current to be mensured.
Letter A
If you notice any mistake in my english, please let me know, because i am not native.
To solve this problem we will apply the concept of Electric Flow, which is understood as the product between the Area and the electric field. For the data defined by the area, we will use the geometric measurement of the area in a circle (By the characteristics of the object) This area will be equivalent to,



Applying the concept of electric flow we have to

Replacing,


Therefore the magnitude of the electric field is 
Answer: v = 2.53 m/s at E 53.1° S
Explanation:
Conservation of momentum
The 400 g object has no North-South velocity, so the initial momentum in that direction is zero. The total momentum after collision must also be zero
0 = 400(8sin35) + 650vy
vy = -2.82376... m/s
In the East direction
400(10) = 400(8cos35) + 650vx
vx = 2.121097...m/s
v = √(2.12² + 2.82²) = 3.531667... ≈ 2.53 m/s
θ = arctan(vy/vx) = arctan(-2.82/2.12) = -53.087... ≈ E53.1°S