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baherus [9]
3 years ago
5

A 35.0-cm-diameter circular loop is rotated in a uniform electric field until the position of maximum electric flux is found. Th

e flux in this position is measured to be 5.42 105 N · m2/C. What is the magnitude of the electric field? MN/C
Physics
1 answer:
MAVERICK [17]3 years ago
7 0

To solve this problem we will apply the concept of Electric Flow, which is understood as the product between the Area and the electric field. For the data defined by the area, we will use the geometric measurement of the area in a circle (By the characteristics of the object) This area will be equivalent to,

\phi = 35 cm

r = 17.5 cm = 0.175 m

A = \pi r^2 = \pi (0.175)^2 = 0.09621m^2

Applying the concept of electric flow we have to

\Phi = EA

Replacing,

5.42*10^5N \cdot m^2/C = E (0.09621m^2)

E = 5.6335*10^6N/C

Therefore the magnitude of the electric field is 5.6335*10^6N/C

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<h2>Answer: Kitty Hawk, North Carolina </h2>

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It should be noted that the Wright brothers only studied until high school, however, their passion for solving the problem of the human inability to fly, their perseverance and experience acquired over the years in their bicycle company, led them to reach that goal. An achievement that marked the beginning of the  aviation era.

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3 years ago
A ball rolls horizontally off a table and a height of 1.4 m with a speed of 4 m/s. How long does it take the ball to reach the g
Hitman42 [59]

For vertical motion, use the following kinematics equation:

H(t) = X + Vt + 0.5At²

H(t) is the height of the ball at any point in time t for t ≥ 0s

X is the initial height

V is the initial vertical velocity

A is the constant vertical acceleration

Given values:

X = 1.4m

V = 0m/s (starting from free fall)

A = -9.81m/s² (downward acceleration due to gravity near the earth's surface)

Plug in these values to get H(t):

H(t) = 1.4 + 0t - 4.905t²

H(t) = 1.4 - 4.905t²

We want to calculate when the ball hits the ground, i.e. find a time t when H(t) = 0m, so let us substitute H(t) = 0 into the equation and solve for t:

1.4 - 4.905t² = 0

4.905t² = 1.4

t² = 0.2854

t = ±0.5342s

Reject t = -0.5342s because this doesn't make sense within the context of the problem (we only let t ≥ 0s for the ball's motion H(t))

t = 0.53s

8 0
3 years ago
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levacccp [35]
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2 years ago
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maw [93]

A. 1/9

Explanation:

The gravitational force between two objects is given by

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m1 and m2 are the two masses

r is the distance between the two masses

From the formula, we see that the magnitude of the force is inversely proportional to the square of the distance: therefore, if the distance is tripled (increased by a factor 3), the magnitude of the force changes by a factor

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victus00 [196]

Answer:

D. the same as force. the applied force per cross-sectional area.

Explanation:

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Hence the unit of Tensile stress is N/m²

6 0
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