All categories

4 years ago

PLEASE HELP ME :( i only need help with question 1, i already did 2 and 3

Physics

1 answer:

iren2701 [21]4 years ago

5 0

Answer:

i think B.

Explanation:

if i get it right can you tell me and if i do can i have brainliest thxs :)

HAVE A WONDERFUL DAYYY :P

You might be interested in

How to measure the density of a white dwarf if its diameter is 1000 km and weighs 10³⁰ kg?

Afina-wow [57]

Well, first of all, 10³⁰ kg is its mass, not its weight.

-- Density of anything is (its mass) divided by (its volume).

-- You know the white dwarf's mass.

-- The volume of any sphere is (4/3) (pi) (radius)³

-- The radius is 1/2 of the diameter.

-- Now you have the ball. Run with it.

I did it quickly and got (1.91 x 10¹²) kilogram/meter³ .
That may be wrong. You have to check it. And even
if it's correct, you probably want to express density in
units of gram/cm³ the way everybody always does.

6 0

3 years ago

An AC generator has 80 rectangular loops on its armature. Each loop is 12 cm long and 8 cm wide. The armature rotates at 1200 rp

Sauron [17]

Answer: 28.96 V

Explanation:

Given

No of loops on the armature, N = 80

Length of the loop, l = 12 cm = 0.12 m

Width of the loop, b = 8 cm = 0.08 m

Speed of the armature, 1200 rpm

Magnetic field of the loop, B = 0.30 T

To solve this, we use the formula

V(max) = NBAω

Where,

A = area of loop

A = l*b = 0.12 * 0.08

A = 0.0096 m²

ω = 1200 rpm = 1200 * 2π/60 rad/s

ω = (1200 * 2 * 3.142) / 60

ω = 7540.8 / 60

ω = 125.68 rad/s

Substituting the values into the formula

V(max) = NBAω

V(max) = 80 * 0.30 * 0.0096 * 125.68

V(max) = 80 * 0.362

V(max) = 28.96 V

Therefore, the maximum output voltage of the generator would be 28.96 V

5 0

3 years ago

A charge Q acts on a point charge to create an electric field. Its strength, measured a distance of 40 cm away is 100 N/C. What

KIM [24]

Answer:

$E_2=80N/C$

Explanation:

From the question we are told that:

Initial Distance $d_1=40cm=>0.4m$

Initial Electric field strength $E_1=100N/C$

Final Distance $d_2=20cm=>0.20m$

Generally the equation for Electric field is mathematically given by.

$E=\frac{kq}{d^2}$

$q=\frac{100*(0.4)^2}{K}$

Substituting q for $d=20cm$

$E_2=\frac{k}{0.2}*\frac{100*(0.4)^2}{K}$

$E_2=80N/C$

6 0

3 years ago

If a rock falls from a cliff, at what point are its kinetic energy and its potential energy the same? Ignore air resistance.

nekit [7.7K]

Answer:

The gravitational potential energy it had from being above the ground is converted to kinetic energy as the rock falls. As kinetic energy increases, the velocity of the rock will also increase.

Explanation:

6 0

3 years ago

Read 2 more answers

An airplane starts its takeoff by moving at 1.7 m/s. The plane must then accelerate at 3.0 m/s2 for the next 30s to reach its fi

otez555 [7]

Answer:

The distance is 1.4 km.

Explanation:

Given that,

Initial velocity u= 1.7 m/s

Accelerate a= 3.0 m/s²