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Finger [1]
3 years ago
13

A body of mass 400 g is moving along a smooth surface at a velocity of 10 m s–1 east. It strikes a body of mass 650 g, initially

at rest, and then the 400 g body moves at a velocity of 8 m s–1 in a direction E35°N. What is the velocity of the 650 g object?
Physics
1 answer:
9966 [12]3 years ago
4 0

Answer: v = 2.53 m/s at E 53.1° S

Explanation:

Conservation of momentum

The 400 g object has no North-South velocity, so the initial momentum in that direction is zero. The total momentum after collision must also be zero

0 = 400(8sin35) + 650vy

vy = -2.82376... m/s

In the East direction

400(10) = 400(8cos35) + 650vx

vx = 2.121097...m/s

v = √(2.12² + 2.82²) = 3.531667... ≈ 2.53 m/s

θ = arctan(vy/vx) = arctan(-2.82/2.12) = -53.087... ≈ E53.1°S

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Explanation:

1)

The angular velocity of an object in circular motion is equal to the rate of change of its angular position. Mathematically:

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In this problem, the Hubble telescope completes an entire orbit in 95 minutes. The angle covered in one entire orbit is

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2)

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\omega=0.0011 rad/s is the angular velocity of the Hubble telescope

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4 0
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