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3 years ago

Write the equation of the vertical line that passes through ordered pair 2.

Mathematics

2 answers:

gayaneshka [121]3 years ago

7 0

Answer: yeah the first answer is a good answer

Step-by-step explanation: have a nice day

damaskus [11]3 years ago

4 0

Answer:

this is a table

y= (a times when y is negative)

X=(X is possitive)

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Kianna has $2.83. Avery has $5.18. They put their money together to buy packages of fruit snacks that each cost $0.30. How many

Nana76 [90]

Answer:

26 snack packs

Step-by-step explanation:

2.83+5.18=8.01

8.01/.30=26.7

26 snack packs

7 0

2 years ago

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1. What is the mean of the data set?

enyata [817]

Answer:

1. mean is 17.4

2. interquartile range is 30

3. mean absolute deviation is 3

4. median is 51

Step-by-step explanation:

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3 years ago

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What Is the value of n? -2/3n= 12

Zielflug [23.3K]

The answer is 18 You divide 12 buy -2/3

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3 years ago

Você é um comandante de uma espaçonave. Sua missão é chegar até Alfa Centauro em cinco anos. A distância do Sol até Alfa Centaur

Deffense [45]

Answer:

The spaceship will get to Alpha Centaur in time

Step-by-step explanation:

The complete question in English is

You're the commander of a spaceship. Your mission is to reach Alpha Centaur in five years. The distance from the sun to Alpha Centaur is 2.5 x 10^13 miles. The distance from Earth to Sun is approximately 9.3 x 10^7

miles. Your spaceship can travel at the speed of light. You know that light can travel a distance of 5.88 x 10^12 miles in a year. Can you get to Alpha Centaur in time?

step 1

Find the time it takes for the spaceship to travel from Earth to the Sun

The distance from the Earth to Sun is equal to

$9.3*10^7\ miles$

The spaceship can travel at the speed of light

The light can travel a distance of $5.88*10^{12}\ miles$ in a year

using a proportion

$\frac{5.88*10^{12}\ miles}{1\ year}=\frac{9.3*10^7\ miles}{x}\\\\x=(9.3*10^7)/5.88*10^{12}\\\\x=1.58*10^{-5} \ years$

This time is very small in years

Convert to minutes

$1.58*10^{-5} \ years=1.58*10^{-5} (365)(24)(60)=8.3\ min$

step 2

Find the time it takes for the spaceship to travel from the Sun to Alpha Centaur

The distance from the the Sun to Alpha Centaur is equal to

$2.5*10^{13}\ miles$

The spaceship can travel at the speed of light

The light can travel a distance of $5.88*10^{12}\ miles$ in a year

using a proportion

$\frac{5.88*10^{12}\ miles}{1\ year}=\frac{2.5*10^{13}\ miles}{x}\\\\x=(2.5*10^{13})/5.88*10^{12}\\\\x=4.25\ years$

$4.25\ years< 5\ years$

therefore

The spaceship will get to Alpha Centaur in time

3 0

2 years ago

Dan bought five new baseball trading cards to add to his collection .The next day his dog ate half of his collection .There are

AleksandrR [38]

-- After dog ate 1/2 of the collection, there were 29 remaining.

-- Just before dog came along, there were (2 x 29) = 58 cards.

-- That was after Dan added 5 new ones.

-- Before he added the 5 new ones, there were (58 - 5) = 53 cards.

-- When this story began, Dan had 53 cards.

8 0

2 years ago

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