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xxMikexx [17]
3 years ago
5

Use order of operation and the mathematical properties of numbers to simplify these numbers (3+2^2)^2 =

Mathematics
2 answers:
Art [367]3 years ago
3 0

Answer:

49

Step-by-step explanation:

(3+2²)²

(3+4)²

(7)²

49

ludmilkaskok [199]3 years ago
3 0

Answer:

Your answer is 49.

Step-by-step explanation:

What you do first is you have to do the exponent in the parenthesis first.

2^2=4 so it will be (3+4)^2.

You will then add 3 and 4 together in the parenthesis to get (7)^2.

You will then square 7 to get 49 as your answer.

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Evalute The Expression 2b+5=2
Snezhnost [94]

Answer:

b = -3/2

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define Equation</u>

2b + 5 = 2

<u>Step 2: Solve for </u><em><u>b</u></em>

  1. Subtract 5 on both sides:                    2b = -3
  2. Divide 2 on both sides:                        b = -3/2
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How many significant digits are in 80,000
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Use f(x)=-2x+5 to find x when f(x)=11
Damm [24]
When it asks this question, ultimately you want to plug 11 into x because its f(x). 11=-2+5.

Then you subtract 5 on both sides because of the opposite of addition is subtraction.

6=-2x

now divide on both sides

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3 0
2 years ago
4. Find the standard from of the equation of a hyperbola whose foci are (-1,2), (5,2) and its vertices are end points of the dia
Ad libitum [116K]

The <em>standard</em> form of the equation of the hyperbola that satisfies all conditions is (x - 2)²/4 - (y - 2)²/5 = 1 .

<h3>How to find the standard equation of a hyperbola</h3>

In this problem we must determine the equation of the hyperbola in its <em>standard</em> form from the coordinates of the foci and a <em>general</em> equation of a circle. Based on the location of the foci, we see that the axis of symmetry of the hyperbola is parallel to the x-axis. Besides, the center of the hyperbola is the midpoint of the line segment with the foci as endpoints:

(h, k) = 0.5 · (- 1, 2) + 0.5 · (5, 2)

(h, k) = (2, 2)

To determine whether it is possible that the vertices are endpoints of the diameter of the circle, we proceed to modify the <em>general</em> equation of the circle into its <em>standard</em> form.

If the vertices of the hyperbola are endpoints of the diameter of the circle, then the center of the circle must be the midpoint of the line segment. By algebra we find that:

x² + y² - 4 · x - 4 · y + 4= 0​

(x² - 4 · x + 4) + (y² - 4 · y + 4) = 4

(x - 2)² + (y - 2)² = 2²

The center of the circle is the midpoint of the line segment. Now we proceed to determine the vertices of the hyperbola:

V₁(x, y) = (0, 2), V₂(x, y) = (4, 2)

And the distance from the center to any of the vertices is 2 (<em>semi-major</em> distance, a) and the semi-minor distance is:

b = √(c² - a²)

b = √(3² - 2²)

b = √5

Therefore, the <em>standard</em> form of the equation of the hyperbola that satisfies all conditions is (x - 2)²/4 - (y - 2)²/5 = 1 .

To learn more on hyperbolae: brainly.com/question/27799190

#SPJ1

5 0
1 year ago
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