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lianna [129]
2 years ago
13

Example 4.4

Physics
1 answer:
Dmitry [639]2 years ago
3 0

Answer:

  • 0.0002012
  • 0.0002192

Explanation:

Using apparent = mass of liquid expelled/mass of liquid remaining × temp. rise

Mass expelled: 250-248.5=1.5g

Mass remaining =248.5g

Temp. rise= 60-30= 30ºc

= 1.5/248.5×30=0.0002012

Using real= apparent + cubic expansivty

Cubic= 3 × linear expansivty

= 3×0.000006=0.000018

0.0002012+0.000018=0.0002192

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A harmonic wave on a string with a mass per unit length of 0.050 kg/m and a tension of 60 N has an amplitude of 5.0 cm. Each sec
Dennis_Churaev [7]

Answer:

Power of the string wave will be equal to 5.464 watt

Explanation:

We have given mass per unit length is 0.050 kg/m

Tension in the string T = 60 N

Amplitude of the wave A = 5 cm = 0.05 m

Frequency f = 8 Hz

So angular frequency \omega =2\pi f=2\times 3.14\times 8=50.24rad/sec

Velocity of the string wave is equal to v=\sqrt{\frac{T}{\mu }}=\sqrt{\frac{60}{0.050}}=34.641m/sec

Power of wave propagation is equal to P=\frac{1}{2}\mu \omega ^2vA^2=\frac{1}{2}\times 0.050\times 50.24^2\times 34.641\times 0.05^2=5.464watt

So power of the wave will be equal to 5.464 watt

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3 years ago
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MrRissso [65]

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He does whatever a spider can. Spider-Man, who has a mass of 76 [kg], is clinging onto an inclined wall forming an inclination a
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Answer:570.54 N

Explanation:

Given

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