Answer:
the maximum height reached by the marble is 11.84 m.
Explanation:
Given;
mass of the marble, m = 0.02 kg
extension of the string, x = 0.08 m
force applied to the string, F = 58 N
Apply the principle of conservation of energy;
elastic potential energy = gravitational potential energy
¹/₂fx = mgh

Therefore, the maximum height reached by the marble is 11.84 m.
Explanation:
Given that,
An object in free fall will fall d feet in t seconds, where d and t are related by the algebraic model as :
..........(1)
(a) We need to find the time taken by the object to fall 1148 ft. Put this in equation (1) as :


t = 8.47 seconds
(b) If the object is in free fall for 18.5 sec after it is dropped, then the height of the object is given by :

d = 5476 ft
Hence, this is the required solution.
Explanation:
Mass of the ball, m = 0.058 kg
Initial speed of the ball, u = 11 m/s
Final speed of the ball, v = -11 m/s (negative as it rebounds)
Time, t = 2.1 s
(a) Let F is the average force exerted on the wall. It is given by :


F = 0.607 N
(b) Area of wall, 
Let P is the average pressure on that area. It is given by :


P = 0.202 Pa
Hence, this is the required solution.
Answer:
n = 1.76
Explanation:
According to the rule of ( n1 sin theta1 = n2 sin theta2 )
we know both angles so we insert them to the law and apply n1 = 1
so 1/2 = n2 sin 62 and we get the final answer