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3 years ago

Match these terms with the correct examples.

2 answers:

4 0

1. liquid solution to a. oceans
2. gaseous solution to b. clouds
Not sure about 3 and 4.
3 might be oxygen but I think that's 5. element.

Hope this helps, not sure about water and air though.

kogti [31]3 years ago

3 0

<h3>Answer:</h3>

1) Liquid solution: Oceans

2) Gaseous Solution: Air

3) Compound: Water

4) Colloid: Cloud

5) Element: Oxygen

<h3>Explanation:</h3>

Solutions are those mixtures which have uniform composition. The size of solute is around 1 Angstrom hence, the particles of solutes can not be seen and the interactions make the overall solution transparent.

Compounds are those substances which are formed chemically by the reaction of two different elements like,

O₂ + 2 H₂ → 2 H₂O

Colloids are also mixtures but these are intermediate between true solutions and suspensions. Also, the solute size is greater than that of solute size in solutions and is about 10 Angstrom. Examples include Clouds, Fog, Moist, Aerosol sprays e.t.c.

Elements are those substances which either are made up of single atoms like noble gases or are molecules made up of same elements like O₂, H₂, Cl₂, N₂ e.t.c.

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A ball of 0.5kg slows down from 5m/s to 3m/s. Calculate the work done inthe process.

dlinn [17]

Answer:

9.8 Joules (rounded to 2 significant figures)

Explanation:

Work done (J)= Force(N) x distance changed (m)

Force= 9.80665 x 0.5kg
Force= 4.90332 Newtons

Distance changed= 5-3
distance changed= 2m/s

--> work done= 4.90332 x 2

work done= 9.8 Joules

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2 years ago

Three forces of magnitude 10N, 5N and 4N act on an object in the directions North, West and East respectively. Find the magnitud

Gekata [30.6K]

Answer:

19N to the south

Explanation:

F =10N + 5N + 4N

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3 years ago

) The radius of sphere measured repeated values 5.63 m, 5.54 m and 5.53 m. Determine the most

Nadusha1986 [10]

Answer:

v_{ average} = 5.57

Explanation:

The most probable value of a measure is

v_average = $\frac{1}{N}$ ∑ x_i

where N is the number of measurements

in tes case N = 3

v_{average} = ⅓ (5.63 +5.54 + 5.53)

V_{average} = 5,567

The number of significant figures must be equal to the number of figures that have the least in the readings.

v_{ average} = 5.57

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2 years ago

Find the cube roots of 27(cos 327° + i sin 327° ). Write the answer in trigonometric form.

Sati [7]

Answer:

$z^{\frac{1}{3} }= -0.978 + i\cdot 2.836$ , $z^{\frac{1}{3} }= -1.967 - i\cdot 2.265$ , $z^{\frac{1}{3} }= 2.945 - i\cdot 0.571$

Explanation:

The cube root of the complex number can determined by the following De Moivre's Formula:

$z^{\frac{1}{n} } = r^{\frac{1}{n} }\cdot \left[\cos\left(\frac{x + 2\pi\cdot k}{n} \right) + i\cdot \sin\left(\frac{x+2\pi\cdot k}{n} \right)\right]$

Where angles are measured in radians and k represents an integer between $0$ and $n - 1$ .

The magnitude of the complex number is $27$ and the equivalent angular value is $1.817\pi$ . The set of cubic roots are, respectively:

k = 0

$z^{\frac{1}{3} } = 3\cdot \left[\cos \left(\frac{1.817\pi}{3} \right)+i\cdot \sin\left(\frac{1.817\pi}{3} \right)]$

$z^{\frac{1}{3} }= -0.978 + i\cdot 2.836$

k = 1

$z^{\frac{1}{3} } = 3\cdot \left[\cos \left(\frac{3.817\pi}{3} \right)+i\cdot \sin\left(\frac{3.817\pi}{3} \right)]$

$z^{\frac{1}{3} }= -1.967 - i\cdot 2.265$

k = 2

$z^{\frac{1}{3} } = 3\cdot \left[\cos \left(\frac{5.817\pi}{3} \right)+i\cdot \sin\left(\frac{5.817\pi}{3} \right)]$

$z^{\frac{1}{3} }= 2.945 - i\cdot 0.571$

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3 years ago

Jorge asked, "Where are the apples?" Which sentence revises the sample sentence to the indicative mood? Where are the apples? Jo

ipn [44]

Answer:

Jorge wanted to know where the apples were

Explanation:

Ya see, I don't want to explain, cuz I guessed. Also I'm on episode 499 of naruto so yeah

8 0

2 years ago

Read 2 more answers