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Ganezh [65]
2 years ago
9

If a cheetah runs 352 meters in 20 seconds, what is the speed of the cheetah?

Physics
1 answer:
valina [46]2 years ago
5 0

Answer:

63360 mi/h

Explanation:

<u>How to find the speed of an object</u>

Calculate speed, distance, or time using the formula d = st, distance equals speed times time. The Speed Distance Time Calculator can solve for the unknown SDT value given two known values.

Time can be entered or solved for in units of second S (s), minutes (min), hours (hr), or hours and minutes and seconds (hh:mm: ss). See shortcuts for time formats below.

To solve for distance use the formula for distance D = st, or distance equals speed times time.

distance = speed x time

Rate and speed are similar since they both represent some distance per unit time like miles per hour or kilometers per hour. If rate r is the same as speed s, r = s = d/t. You can use the equivalent formula d = rt which means distance equals rate times time.

distance = rate x time

To solve for speed or rate use the formula for speed, s = d/t which means speed equals distance divided by time.

speed = distance/time

To solve for time use the formula for time, t = d/s which means time equals distance divided by speed.

time = distance/speed

Therefore, the speed = 63360 miles per hour

= 63360 mi/h

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A ball is gently dropped from a height of 20 m. If its velocity Increases uniformly at the rate of 10 m s2, with what velocity w
Pie

Answer:

20 m/s

Explanation:

Height (s)= 20m

acceleration (a) = 10 m/s^2

v=?

we know,

V^2= U^2 + 2as. (U is initial velocity)

or,. V^2 = 0 + 2 × 10 × 20

or, V^2 = 400

or,. V = 20 m/s

5 0
2 years ago
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lens is to be used to allow this eye to clearly focus on objects 25 cm in front of it. What should be the focal length of this l
ser-zykov [4K]
<h2>Question: </h2>

The nearpoint of an eye is 151 cm. A corrective lens is to be used to allow this eye to clearly focus on objects 25 cm in front of it. What should be the focal length of this lens?

Answer:

29.96cm

Explanation:

Using the corrective lens, the image should be formed at the front of the eye and be upright and virtual.

Now using the lens equation as follows;

\frac{1}{f} = \frac{1}{v} + \frac{1}{u}   -------------(i)

Where;

f = focal length of the lens

v = image distance as seen by the lens

u = object distance from the lens

From the question;

v = -151cm        [-ve since the image formed is virtual]

u = 25cm

Rewrite equation (i) to have;

f = \frac{uv}{u+v}

Substitute the values of v and u into the equation;

f = \frac{25*(-151)}{25-151}

f = \frac{-3775}{-126}

f = 29.96cm

The focal length should be 29.96cm

4 0
3 years ago
A small 12.00g plastic ball is suspended by a string in a uniform, horizontal electric field with a magnitude of 10^3 N/C. If th
tensa zangetsu [6.8K]

Answer:

The net charge is 67.89 \mu C

Solution:

As per the question:

Mass of the plastic bag, m = 12.0 g = 12.0\times 10^{-3}\ kg

Magnitude of electric field, E = 10^{3}\ N/C

Angle made by the string, \theta = 30^{\circ}

Now,

To calculate the net charge, Q on the ball:

Vertical component of the tension in the string, T = Tcos\theta

Horizontal component of the tension in the string, T = Tsin\theta

Now,

Balancing the forces in the x-direction:

Tsin\theta = QE

Q = {Tsin\theta}{E}                             (1)

Balancing the forces in the y-direction:

Tcos\theta = mg

where

g = acceleration due to gravity = 9.8\ m/s^{2}

Thus

T = \frac{mg}{cos\theta }

T = \frac{12.0\times 10^{-3}\times 9.8}{cos30^{\circ}} = 0.1357\ N

Use T = 0.1357 N in eqn (1):

Q = {0.1357\times sin30^{\circ}}{10^{3}} = 6.789\times 10^{- 5}\ C

Q = 67.89\times 10^{- 5}\ C = 67.89\mu C

7 0
3 years ago
This is a compound made from a group of covalently bonded atoms.
ra1l [238]
The answer is molecule
3 0
3 years ago
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HELP FAST!!!!!!!
Alex17521 [72]

<u>Answer</u>

A. Metals A and metals B



<u>Explanation</u>

Heat transfer takes place whenever there is temperature difference. When two bodies of different temperatures are brought together, heat energy will move from one body to the other until equilibrium temperature is reached.

In our case, heat transfer will take place in all four metals.

Metal A will transfer heat to the water since it's temperature is higher than that of water.

Metal B will also transfer heat to the water since it's temperature is higher than that of water.

Metal C will get heat from the water since it's colder than the water.

Metal D will also get heat from the water since it is colder than water.

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3 years ago
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