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3 years ago

Why is cathode positive in leclanche cell??

Physics

1 answer:

laila [671]3 years ago

7 0

Answer:

Because the zinc is reluctant

Explanation:

A leclanche cell contains a conducting solution (electrolyte) of ammonium chloride, a cathode (positive terminal) of carbon, a depolarizer of manganese dioxide (oxidizer), and an anode (negative terminal) of zinc (reductant).

As the Zn2+ ions move away from the anode, leaving their electrons on its surface,

Zn → Zn2+ + 2e−

the anode becomes more negatively charged than the cathode. When the cell is connected to an external electrical circuit, the excess electrons on the zinc anode flow through the circuit to the carbon rod, the movement of electrons forming an electric current.

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Based on the information in the graph, why is energy released during the fusion of hydrogen (H) into helium (He)?

MrMuchimi

Answer:

Explanation:

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2 years ago

The force that opposes motion to moving parts is _____

Colt1911 [192]

The force that opposes motion to moving parts is F<span>riction</span><span>

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3 years ago

Certain neutron stars (extremely dense stars) are believed to be rotating at about 10 rev/s. If such a star has a radius of 18 k

Aleks [24]

Answer:

mass of the neutron star =3.45185×10^26 Kg

Explanation:

When the neutron star rotates rapidly, a material on its surface to remain in place, the magnitude of the gravitational acceleration on the central material must be equal to magnitude of the centripetal acc. of the rotating star.

That is

$\frac{GM_{ns}}{R^2}= \omega^2 R$

M_ns = mass odf the netron star.

G= gravitational constant = 6.67×10^{-11}

R= radius of the star = 18×10^3 m

ω = 10 rev/sec = 20π rads/sec

therefore,

$M_{ns}= \frac{\omega^2R^3}{G} = \frac{4\pi^2\times(18\times10^3)^3}{6.67\times10^{-11}}$

= 3.45185... E26 Kg

= 3.45185×10^26 Kg

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3 years ago

Cake batter, which is made of things such as sugar, eggs, and flour, is usually smooth and creamy.

Minchanka [31]

Heterogeneous mixture

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3 years ago

Read 2 more answers

An astronaut is in equilibrium when he is positioned 140 km from the center of asteroid X and 581 km from the center of asteroid

mariarad [96]

Answer:

0.05806

Explanation:

$m_x$ = Mass of asteroid x

$m_y$ = Mass of asteroid y

$r_x$ = Distance from asteroid x = 140 km

$r_y$ = Distance from asteroid y = 581 km

m = Mass of asteroid

Force of gravity between asteroid x and the astronaut

$F_1=\frac{Gm_xm}{r_x^2}\\\Rightarrow F_1=\frac{Gm_xm}{140^2}$

Force of gravity between asteroid x and the astronaut

$F_2=\frac{Gm_ym}{r_y^2}\\\Rightarrow F_2=\frac{Gm_ym}{581^2}$

Here these two forces are equal as they are in equilibrium

$\frac{Gm_xm}{140^2}=\frac{Gm_ym}{581^2}\\\Rightarrow \frac{m_x}{140^2}=\frac{m_y}{581^2}\\\Rightarrow \frac{m_x}{m_y}=\frac{140^2}{581^2}\\\Rightarrow \frac{m_x}{m_y}=0.05806$

The ratio of the masses of the asteroid is 0.05806

4 0

3 years ago