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Snezhnost [94]
2 years ago
7

A 1-kilogram stone is being dropped from a bridge 100 meters above a gorge.

Physics
2 answers:
ipn [44]2 years ago
6 0
<h2><u>ANSWER</u><u>:</u></h2>

<h3><u>C</u><u>.</u><u> </u><u>1</u><u>0</u><u>0</u><u> </u><u>NEWTONS</u></h3>

<h2><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u></h2>

<u>CARRY</u><u> </u><u>ON</u><u> LEARNING</u>

<u>CAN</u><u> </u><u>Y</u><u>OU</u><u> BRAINLEST</u><u> ME</u>

ziro4ka [17]2 years ago
4 0

Answer:

C. 100 NEWTONS

Explanation:

just my brain being ly = brainly is the name so my brian is being ly

You might be interested in
Tenses of<br>write=<br>read=<br><br>​
PilotLPTM [1.2K]

Answer:

present

Explanation:

read doesn't change but write is in present tense

7 0
3 years ago
If 175 kJ of heat caused a chunk of ice at 0°C to melt to liquid water at 0°C, how many moles were in the ice? How many grams of
elena55 [62]

Answer is 29.1 mol or 525 g

Explanation:

8 0
3 years ago
Light of frequency 2.5 x 1015 Hz illuminates a
Nikitich [7]

Answer:

h f = W + KE

Input energy equals work function plus KE of emitted electron

W = 6.63E-34 * 2.5E15 - 6.3 * 1.6E-19

W = 6.63 * 2.5 * 10^-19 - 10.1 * E-19 ev     (1ev = 1.6E-19 J)

W = (16.6 - 10.1)E-19 = 6.5E-19 J

h f = 6.5E-19 J        for electrons to be emitted with zero KE

f = 6.5E-19 / 6.63E-34 = .98E-15 / sec = 9.8E-14 / sec  (threshold)

3 0
2 years ago
You have a 2m long wire which you will make into a thin coil with N loops to generate a magnetic field of 3mT when the current i
Anni [7]

Answer:

<em>radius of the loop =  7.9 mm</em>

<em>number of turns N ≅ 399 turns</em>

Explanation:

length of wire L= 2 m

field strength B = 3 mT = 0.003 T

current I = 12 A

recall that field strength B = μnI

where n is the turn per unit length

vacuum permeability μ  = 4\pi *10^{-7}  T-m/A = 1.256 x 10^-6 T-m/A

imputing values, we have

0.003 = 1.256 x 10^−6 x n x 12

0.003 = 1.507 x 10^-5 x n

n = 199.07 turns per unit length

for a length of 2 m,

number of loop N = 2 x 199.07 = 398.14 ≅ <em>399 turns</em>

since  there are approximately 399 turns formed by the 2 m length of wire, it means that each loop is formed by 2/399 = 0.005 m of the wire.

this length is also equal to the circumference of each loop

the circumference of each loop = 2\pi r

0.005 = 2 x 3.142 x r

r = 0.005/6.284 = 7.9*10^{-4} m = 0.0079 m =<em> 7.9 mm</em>

8 0
3 years ago
The magnitude of the electrical force acting between a +2.4 × 10–8 C charge and a +1.8 × 10–6 C charge that are separated by 0.0
monitta
Use Coulomb law: F = k * q1*q2 / (r^2), where k = 9.00 * 10^9 N.m^2/C^2

F = 9.00 * 10^9 N.m^2/C^2 * 2.4*10^-8 C * 1.8*10^-6 C / [0.008m]^2 = 38.88 * 10^ -5 N

F = 39 * 10 -5N


4 0
3 years ago
Read 2 more answers
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