Answer:
Positively charged nuclei are packed in an organized pattern, and the negatively charged valence electrons flow freely.
Explanation:
V₁ = (1/g)₁ = Way₁ = 20(9.81)(0) = 0
V₂ (Vg)₂ = -WAy₂ = -20(9.81)(0.5) = -98.1J
The kinetic energy because the pool rotates about a fixed axis
W = VA/rA = VA/0.2 5VA
Mass momen of inertila about fixed axis which passes through point 0
I₀ = mko² = 50(0.280)² = 3.92 kg. m²
∴ The kinetic energy of the system is
T = 1/2 I₀w² + 1/2mAVA²
= 1/2(3.92)(5VA)² + 1/2 (20) VA² = 59VA²
Now that the system is at rest then T₁ = 0
Energy conservation is
T₁ +V₁ = T₂ + V₂
0+ 0 = 59VA² + (-98.1)
VA = 1.289 m/s
= 1.29 m/s
Answer:

Explanation:
Where E is the magnitude of electric field...
k is called Columb's Constant. It has a value of 8.99 x 109 N m2/C2.
Qs is the magnitude of the source charge...
and r is the magnitude of distance between source and target...
(When electron comes to rest Δt the magnitude of Electric field E become zero momentarily but later achieves the maximum value...)
Answer: B 100 J
Explanation: Pic Attached. Hope This Helps.
C im pretty sure?.........