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Levart [38]
3 years ago
7

A car is traveling to the right with a speed of 29\,\dfrac{\text m}{\text s}29

Physics
1 answer:
ryzh [129]3 years ago
4 0
Burn us bud ijdghdhd jdnjdbd handguns jsbgd bdhdhfbdj hdjdhdhdh
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A school bus full of students drives down the road. Because it is moving, it has 1.potential energy because it has the ability t
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<span>Kinetic energy because it is taking the students to school.</span>
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List any similarities between discovered exoplanets and planets in our solar system.
gregori [183]

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1. Revolve around a point

2. Formed from dust and gas particles

3. Exoplanets and associated star orbit a common center of mass  

4. Composed of gases found in Jupiter and Saturn

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3 years ago
If a substance has a density of 2.7g/cm3 and a mass of 86.4g, what is its volume?
Gennadij [26K]

Answer:

32cm³

Explanation:

Given parameters:

  Density of substance  = 2.7g/cm³

   Mass of substance  = 86.4g

Unknown:

Volume of substance  = ?

Solution:

Density is the mass per unit volume of a substance.

    Density  = \frac{mass}{volume}

Since the unknown is volume we solve for it;

   mass  = density x volume

   86.4 = 2.7 x volume

    volume  = \frac{86.4}{2.7}   = 32cm³

7 0
3 years ago
A baseball, which has a mass of 0.685 kg., is moving with a velocity of 38.0 m/s when it contacts the baseball bat duringwhich t
Evgen [1.6K]

Answers:

a) 65.075 kgm/s

b) 10.526 s

c) 61.82 N

Explanation:

<h3>a) Impulse delivered to the ball</h3>

According to the Impulse-Momentum theorem we have the following:

I=\Delta p=p_{2}-p_{1} (1)

Where:

I is the impulse

\Delta p is the change in momentum

p_{2}=mV_{2} is the final momentum of the ball with mass m=0.685 kg and final velocity (to the right) V_{2}=57 m/s

p_{1}=mV_{1} is the initial momentum of the ball with initial velocity (to the left) V_{1}=-38 m/s

So:

I=\Delta p=mV_{2}-mV_{1} (2)

I=\Delta p=m(V_{2}-V_{1}) (3)

I=\Delta p=0.685 kg (57 m/s-(-38 m/s)) (4)

I=\Delta p=65.075 kg m/s (5)

<h3>b) Time </h3>

This time can be calculated by the following equations, taking into account the ball undergoes a maximum compression of approximately 1.0 cm=0.01 m:

V_{2}=V_{1}+at (6)

V_{2}^{2}=V_{1}^{2}+2ad (7)

Where:

a is the acceleration

d=0.01 m is the length the ball was compressed

t is the time

Finding a from (7):

a=\frac{V_{2}^{2}-V_{1}^{2}}{2d} (8)

a=\frac{(57 m/s)^{2}-(-38 m/s)^{2}}{2(0.01 m)} (9)

a=90.25 m/s^{2} (10)

Substituting (10) in (6):

57 m/s=-38 m/s+(90.25 m/s^{2})t (11)

Finding t:

t=1.052 s (12)

<h3>c) Force applied to the ball by the bat </h3>

According to Newton's second law of motion, the force F is proportional to the variation of momentum  \Delta p in time  \Delta t:

F=\frac{\Delta p}{\Delta t} (13)

F=\frac{65.075 kgm/s}{1.052 s} (14)

Finally:

F=61.82 N

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3 years ago
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Directions: Complete the concept map using the terms listed below.
Komok [63]

Answer:

this is confusing

Explanation:

6 0
3 years ago
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