<h2>MARK BRAINLIEST</h2>
For this assignment, you will develop several models that show how light waves and mechanical waves are reflected, absorbed, or transmitted through various materials. For each model, you will write a brief description of the interaction between the wave and the material. You will also compose two <u><em>typewritten</em></u> paragraphs. The first will compare and contrast light waves interacting with different materials. The second will explain why materials with certain properties are well suited for particular functions.
<h2><u>Background Information</u></h2>
A wave is any disturbance that carries energy from one place to another. There are two different types of waves: mechanical and electromagnetic. A mechanical wave carries energy through matter. Energy is transferred through vibrating particles of matter. Examples of mechanical waves include ocean waves, sound waves, and seismic waves. Like a mechanical wave, an electromagnetic wave can also carry energy through matter. However, unlike a mechanical wave, an electromagnetic wave does not need particles of matter to carry energy. Examples of electromagnetic waves include microwaves, visible light, X-rays, and radiation from the Sun.
Answer:
The coefficient of kinetic friction between the sled and the snow is 0.0134
Explanation:
Given that:
M = mass of person = 52 kg
m = mass of sled = 15.2 kg
U = initial velocity of person = 3.63 m/s
u = initial velocity of sled = 0 m/s
After collision, the person and the sled would move with the same velocity V.
a) According to law of momentum conservation:
Total momentum before collision = Total momentum after collision
MU + mu = (M + m)V
![V=\frac{MU+mu}{M+m}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7BMU%2Bmu%7D%7BM%2Bm%7D)
Substituting values:
![V=\frac{MU+mu}{M+m}=\frac{52(3.63)+15.2(0)}{52+15.2} =2.81m/s](https://tex.z-dn.net/?f=V%3D%5Cfrac%7BMU%2Bmu%7D%7BM%2Bm%7D%3D%5Cfrac%7B52%283.63%29%2B15.2%280%29%7D%7B52%2B15.2%7D%20%3D2.81m%2Fs)
The velocity of the sled and person as they move away is 2.81 m/s
b) acceleration due to gravity (g) = 9.8 m/s²
d = 30 m
Using the formula:
![V^2=2\mu(gd)\\\mu=\frac{V^2}{2gd} \\\mu=\frac{2.81^2}{2*9.8*30} =0.0134](https://tex.z-dn.net/?f=V%5E2%3D2%5Cmu%28gd%29%5C%5C%5Cmu%3D%5Cfrac%7BV%5E2%7D%7B2gd%7D%20%5C%5C%5Cmu%3D%5Cfrac%7B2.81%5E2%7D%7B2%2A9.8%2A30%7D%20%3D0.0134)
The coefficient of kinetic friction between the sled and the snow is 0.0134
Answer:
Hits per second=199 hit/s
Explanation:
#Given the angular velocity,
, radius of the record
and the distance between any two successive bumps on the groove as
.
The linear speed of the record in meters per second is:
![v=\omega r=33\frac{1}{3}\times\frac{2\pi}{60}\times 10\times 10^{_2}\\\\=0.3843m/s\\](https://tex.z-dn.net/?f=v%3D%5Comega%20r%3D33%5Cfrac%7B1%7D%7B3%7D%5Ctimes%5Cfrac%7B2%5Cpi%7D%7B60%7D%5Ctimes%2010%5Ctimes%2010%5E%7B_2%7D%5C%5C%5C%5C%3D0.3843m%2Fs%5C%5C)
#From
above, if the bumps are uniformly separated by 1m, then the rate at which they hit the stylus is:
![Hits/second=v/d \ \ \ \ d=1.75mm\\\\=0.3483/0.000175\\\\=199.0385714\approx 199](https://tex.z-dn.net/?f=Hits%2Fsecond%3Dv%2Fd%20%20%20%20%5C%20%5C%20%5C%20%5C%20d%3D1.75mm%5C%5C%5C%5C%3D0.3483%2F0.000175%5C%5C%5C%5C%3D199.0385714%5Capprox%20199)
Hence the bumps hit the stylus at around 199hit/s