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maw [93]
1 year ago
14

at the surface of a freshwater spring, a manatee with a small amount of air in its lungs is neutrally buoyant. the manatee now d

ives to a depth of 10 m.
Physics
1 answer:
Bezzdna [24]1 year ago
8 0

At a depth of 10 m, the manatee's neutral buoyancy keeps it at the same level in water as if there were no air inside its lungs. However, because more air is now contained in the manatee's lungs than before it dove, its weight increases by 9.81 kg and therefore it accelerates downwards (due to momentum). This downward acceleration continues until equilibrium is reached and then ceases due to gravity pulling on both objects equally.

As a result, the manatee now becomes negatively buoyant and must rise to compensate.

<h3>What does it mean when something has neutral buoyancy?</h3>

When something has neutral buoyancy, it is not affected by the weight of anything above or below it.

This means that objects with neutral buoyancy will stay in place regardless of how high or low they are located in a liquid medium.

Examples of things with neutral buoyancy include air balloons and swimming caps.

To learn more about neutral buoyancy, visit:

brainly.com/question/2170899

#SPJ4

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Read 2 more answers
The electric field strength E 0 E 0 is measured at a perpendicular distance R R from an infinitely large, thin sheet that contai
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Answer:

same value in R and 2R       E = E₀ = σ / 2ε₀

Explanation:

For this exercise we use Gauss's law

            Ф = E. dA = q_{int} /ε₀

We define a Gaussian surface with a cylinder with the base being parallel to the load sheet, so the electic field line and the normal line to the base are parallel and the scalar product is reduced to the algebraic product, in the parts the angle is 90º and the dot product is zero

As the sheet has two faces

           2E A = q_{int} /ε₀

The charge inside the cylinder is

           σ = q_{int} / A

           q_{int} = σ A

               

We substitute

           E = σ / 2ε₀

We see that this expression is independent of the distance, so it has the same value in R and 2R

             E = E₀ = σ / 2ε₀

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