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3 years ago

Naomi asked several classmates how much cash they had in their pocket. She recorded the data below:

Mathematics

1 answer:

devlian [24]3 years ago

8 0

Answer:

She arrived at school 23 minutes later. At what time did. Veronica arrive at school? (3.MD.A.1). 12. ... same way they have measured objects to the nearest inch: ... Students will then use line plots as a tool to record ... line plots your classmates ... Ask students to determine how many of ... Pedro has a dollar bill in his pocket.

Step-by-step explanation:

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A bicycle cost $ 129.50. You pay $7.77 in sales tax. What is the tax rate?

viva [34]

7.77/129.5 = 0.06
Therefore the tax rate is 6%

6 0

2 years ago

Name the place of the highlighted digit

enot [183]

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2 years ago

Rueben sells electronics. He earns a 5% commission on each sale he makes. If Ruben wants to make $100 in commission, what is the

Alecsey [184]

Answer:

It is 20

Step-by-step explanation:

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2 years ago

There are 100 people in a wedding house, including children, men and women, and there are 100 pappadas to give with Sadya Te.

olga nikolaevna [1]

Answer:

Two possible sets of answers.

5 men, 11 women and 42 children, or

10 men, 2 women and 88 children

Selamat Sadhya!

Step-by-step explanation:

M = number of men

W = number of women

100-M-W = number of children

Total number of pappadas

5M+3W+(100-M-W)/2 = 100

Solve for W

W = (100-9M)/5 .......................(1)

Examine equation (1).

In order to have W as a whole number, M must be multiple of 5

Therefore M = 5 or 10

If M = 5, W = (100-45)/5 = 11 and children = 100-5-11 = 84

If M = 10, W = (100-90)/5 = 2 and children = 100-10-2 = 88

8 0

2 years ago

The family of solutions to the differential equation y ′ = −4xy3 is y = 1 √ C + 4x2 . Find the solution that satisfies the initi

slega [8]

Answer:

The correct option is 4

Step-by-step explanation:

The solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}$

Now for the initial condition the value of C is calculated as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16$

So the solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}$

Simplifying the equation as

$y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1-256+64x^2}{16}}}\\y(x)=\frac{\sqrt{16}}{\sqrt{{1-256+64x^2}}}\\y(x)=\frac{4}{\sqrt{{1+64(x^2-4)}}}$

So the correct option is 4

8 0

2 years ago

Read 2 more answers