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barxatty [35]
3 years ago
13

All of the covalent carbon-carbon bonds in unsaturated hydrocarbons share 2 pairs of electrons.

Chemistry
2 answers:
Evgen [1.6K]3 years ago
5 0

False. carbon-carbon bonds that share 2 pairs of electrons are double bonds. An unsaturated hydrocarbon isnt necessary to only have double bonds. they can also have single bonds or triple bonds.

IgorLugansk [536]3 years ago
5 0

Answer: The given statement is false.

Explanation:

An unsaturated hydrocarbon is a chain of carbon and hydrogen atoms in which adjacent carbon atoms are attached together through double or triple bond.

Since it is known that carbon atom forms covalent compounds so, an unsaturated hydrocarbon not only contains double or triple bonds it also has single bonds in between.

Thus, we can conclude that the statement all of the covalent carbon-carbon bonds in unsaturated hydrocarbons share 2 pairs of electrons, is false.

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What led Marie Curie to draw the following conclusions? (b) A highly radioactive element, aside from uranium, occurs in pitchble
AVprozaik [17]

Making repeated separations of the various substances in the pitchblende, Marie and Pierre used the Curie electrometer to identify the most radioactive fractions. They thus discovered that two fractions, one containing mostly bismuth and the other containing mostly barium, were strongly radioactive.

<h3>What was surprising about pitchblende?</h3>

Since it was no longer appropriate to call them “uranic rays,” Marie proposed a new name: “radioactivity.”

Even more surprising, Marie next found that a uranium ore called pitchblende contained two powerfully radioactive new elements: polonium, which she named for her native Poland, and radium.

<h3>Why is radium more radioactive than uranium?</h3>

It is 2.7 million times more radioactive than the same molar amount of natural uranium (mostly uranium-238), due to its proportionally shorter half-life.

Learn more about highly radioactive elements here:

<h3>brainly.com/question/10257016</h3><h3 /><h3>#SPJ4</h3>

6 0
1 year ago
How many moles are in 1.51x10^26 atoms of xenon (Xe)? Please and thank you :)!!
RoseWind [281]
<h3>Answer:</h3>

251 mol Xe

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.51 × 10²⁶ atoms Xe

[Solve] moles Xe

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 1.51 \cdot 10^{26} \ atoms \ Xe(\frac{1 \ mol \ Xe}{6.022 \cdot 10^{23} \ atoms \ Xe})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 250.747 \ mol \ Xe

<u>Step 4: Check</u>

<em>Follow sig fig rule and round. We are given 3 sig figs.</em>

250.747 mol Xe ≈ 251 mol Xe

3 0
3 years ago
10. How much protein one should obtain from diet<br> (1 gram, 3 gram,4gram)
jarptica [38.1K]

How much protein one should obtain from diet

Answer:

4 gram

7 0
3 years ago
Read 2 more answers
Which law was used to determine the relationship between the volume and the number of moles?​
lawyer [7]

Answer:

The Mole-Volume Relationship: Avogadro's Law. A plot of the effect of temperature on the volume of a gas at constant pressure shows that the volume of a gas is directly proportional to the number of moles of that gas. This is stated as Avogadro's law.

Explanation:

4 0
3 years ago
1. 17.0 grams of xenon hexafluoride is in a solid container. How many milliliters of that gas
BlackZzzverrR [31]

Answer: The volume of gas is 3020 ml

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 821.4 torr =  1.08 atm     (760 torr = 1atm)

V = Volume of gas in L = ?

n = number of moles = \frac{\text {given mass}}{\text {Molar mass}}=\frac{17.0g}{245.28g/mol}=0.069mol

R = gas constant =0.0821Latm/Kmol

T =temperature =302.7^0C=(302.7+273)K=575.7K

V=\frac{nRT}{P}

V=\frac{0.069mol\times 0.0821Latm/K mol\times 575.7K}{1.08atm}=3.02L=3020ml

Thus volume of gas is 3020 ml

4 0
3 years ago
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