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barxatty [35]
3 years ago
13

All of the covalent carbon-carbon bonds in unsaturated hydrocarbons share 2 pairs of electrons.

Chemistry
2 answers:
Evgen [1.6K]3 years ago
5 0

False. carbon-carbon bonds that share 2 pairs of electrons are double bonds. An unsaturated hydrocarbon isnt necessary to only have double bonds. they can also have single bonds or triple bonds.

IgorLugansk [536]3 years ago
5 0

Answer: The given statement is false.

Explanation:

An unsaturated hydrocarbon is a chain of carbon and hydrogen atoms in which adjacent carbon atoms are attached together through double or triple bond.

Since it is known that carbon atom forms covalent compounds so, an unsaturated hydrocarbon not only contains double or triple bonds it also has single bonds in between.

Thus, we can conclude that the statement all of the covalent carbon-carbon bonds in unsaturated hydrocarbons share 2 pairs of electrons, is false.

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If a question cannot be tested and observed, it cannot be answered with science. (2 points) True or False?
boyakko [2]

Answer:

True

Explanation:

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Consider the following equilibrium:
Ainat [17]

<u>Answer: </u>The equation which is wrong is K_p=K_c(RT)^{-5}

<u>Explanation:</u>

For the given reaction:

4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)

The expression for K_c\text{ and }K_p is given by:

K_c=\frac{1}{[O_2]^3}

K_p=\frac{1}{[O_2]^3}

The concentration of solids are taken to be 1, only concentration of gases and liquid states are taken. The pressure of only gases are taken.

Relationship between K_p\text{ and }K_c is given by the expression:

K_p=K_c\times (RT)^{\Delta n_g}

where,

\Delta n_g= number of moles of gaseous products - number of moles of gaseous reactants

R = gas constant

T= temperature

For the above reaction,

\Delta n_g = number of moles of gaseous products - number of moles of gaseous reactants = 0 - 3 = -3

Hence, the expression for K_p is:

K_p=K_c\times (RT)^{-3}

Therefore, the equation which is wrong is K_p=K_c(RT)^{-5}

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Molal or molar? There is a difference
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