Explanation:
during this reaction this will produce 2 molecules of No
Answer: There are 576.46 number of grams present in 16.95 mol hydrogen peroxide
.
Explanation:
Number of moles is defined as the mass of substance divided by its molar mass.
The molar mass of
is 34.01 g/mol. Hence, mass of hydrogen peroxide present in 16.95 moles is calculated as follows.

Thus, we can conclude that there are 576.46 number of grams present in 16.95 mol hydrogen peroxide
.
H₂SO₄ + 2NaOH = Na₂SO₄ + 2H₂O
v(NaOH)=46 ml=0.046 l
c(NaOH)=1.0 mol/l
v(H₂SO₄)=55 ml=0.055 l
n(NaOH)=v(NaOH)*c(NaOH)
n(H₂SO₄)=0.5n(NaOH)
c(H₂SO₄)=n(H₂SO₄)/v(H₂SO₄)=0.5*v(NaOH)*c(NaOH)/v(H₂SO₄)
c(H₂SO₄)=0.5*0.046*1.0/0.055=0.418 mol/l
The concentration of the H₂SO₄ is 0.418M.