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Pavel [41]
2 years ago
9

Aqueous hydrobromic acid HBr will react with solid sodium hydroxide NaOH to produce aqueous sodium bromide NaBr and liquid water

H2O . Suppose 4.9 g of hydrobromic acid is mixed with 3.86 g of sodium hydroxide. Calculate the maximum mass of sodium bromide that could be produced by the chemical reaction. Round your answer to 2 significant digits.
Chemistry
1 answer:
Studentka2010 [4]2 years ago
5 0

Answer:

6.2g of NaBr are produced

Explanation:

The reaction of HBr with NaOH occurs as follows:

HBr + NaOH → NaBr + H2O

<em>Where 1 mole of each reactant produce 1 mole of NaBr</em>

To solve this question we need to find the moles of each reactant using their molar mass. With moles we can find limiting reactant and the moles (And mass) of NaBr produced, as follows:

<em>Moles HBr -Molar mass: 80.9119g/mol)-</em>

4.9g * (1mol/80.9119g) = 0.0606 moles HBr

<em>Moles NaOH -Molar mass: 40g/mol-</em>

3.86g * (1mol/40g) = 0.0965 moles NaOH

As the reaction is 1:1 and the moles of HBr < Moles NaOH, the limiting reactant is HBr and moles of NaBr produced are 0.0606 moles.

The mass of NaBr (Molar mass: 102.894g/mol) is:

0.0606 moles * (102.894g/mol) =

<h3>6.2g of NaBr are produced</h3>
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Magnesium has three naturally occurring isotopes with masses of 23.99 amu, 24.99 amu, and 25.98 amu and natural abundances of 78
mihalych1998 [28]

Answer:24.31

Explanation:Contribution made by isotope of mass 23.99= 23.99×78.99=1894.97

Contribution made by isotope of mass 24.99=24.99×10.00=249.9

Contribution made by isotope of mass 25.98=25.98×11.01=286.04

Total contribution=1894.97+249.9+286.04=2430.91

Average mass=2430.91÷100

=24.31

3 0
3 years ago
A steel cylinder of oxygen is being store in a room at 25.0 °C under a pressure of 1250 atm. What pressure would be exerted by t
Rudik [331]

Answer:

P₂ = 1312.88 atm

Explanation:

Given data:

Initial temperature = 25°C

Initial pressure = 1250 atm

Final temperature = 40°C

Final pressure = ?

Solution:

Initial temperature = 25°C (25+273.15 = 298.15 K)

Final temperature = 40°C ( 40+273.15 = 313.15 k)

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

1250 atm / 298.15 K = P₂/313.15 K

P₂ = 1250 atm × 313.15 K / 298.15 K

P₂ = 391437.5 atm. K /298.15 K

P₂ = 1312.88 atm

6 0
3 years ago
Un tanque de acetileno para una antorcha de soldadura de oxiacetileno proporciona 9340 L de gas acetileno, C2H2, a 0°C y 1 atm 2
Helen [10]

Answer:

3.33 tanques de O₂

Explanation:

Basados en la reacción:

2C₂H₂(g) + 5O₂(g) → 4CO₂(g) + 2H₂O(g)

<em>2 moles de acetileno reaccionan con 5 moles de oxígeno produciendo 4 moles de dióxido de carbono y 2 moles de agua</em>

<em />

La ley de Avogadro dice que el volumen de un gas bajo temperatura y presión constantes es proporcional a las moles de este gas. Así, como 2 moles de acetileno reaccionan con 5 moles de oxígeno, los litros de O₂ necesarios para quemar 9340L de acetileno son:

9340 L C₂H₂ × (5 moles O₂ / 2 moles C₂H₂) = <em>23350L de O₂</em>

Si un tanque contiene 7x10³ L de O₂ serán necesarios:

23350L O₂ ₓ (1 tanque / 7x10³L) =<em> 3.33 tanques de O₂</em>

6 0
3 years ago
Please Help! Asap! :)
yaroslaw [1]

I need details to solve for you

3 0
3 years ago
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The reaction between carbon tetrachloride, CCl4, and water, H2O, to form carbon dioxide, CO2, and hydrogen chloride, HCl, has a
Ber [7]

Answer:

1) a) It is a slow reaction kinetically.

2) a) It is a catalyst.

3) c) It lowered the activation energy of the reaction.

Explanation:

<em>1) The reaction between carbon tetrachloride, CCl₄, and water, H₂O, to form carbon dioxide, CO₂, and hydrogen chloride, HCl, has a ΔG° value of -232 kJ/mole, and so is thermodynamically favored. But when you mix carbon tetrachloride with water, no change is observed. What is a possible explanation for this? </em>

<em>a) It is a slow reaction kinetically.</em>  TRUE. This is the most likely explanation of why no change is observed.

<em>b) The activation energy of the reaction is too small.</em>  FALSE. Slow reactions have a large activation energy.

<em>c) The reaction is not spontaneous. </em> FALSE. ΔG° < 0 so the reaction is spontaneous.

<em>d)The reaction is not favored thermodynamically.</em> FALSE. ΔG° < 0 so the reaction is favored thermodynamically.

<em>2) What word best describes the role that the palladium plays in the reaction between propene and hydrogen above?</em>

It is a catalyst because it increases the rate of the reaction without being altered by the end of the reaction.

<em>3) What did the palladium do to increase the rate of the reaction between the propene and hydrogen? </em>

<em>a)It changed the thermodynamic equilibrium.</em>  FALSE. Catalysts don't affect equilibrium

<em> b)It made the Gibbs free energy of the reaction more positive.</em>  FALSE. Catalysts don't affect Gibbs free energy.

<em>c)It lowered the activation energy of the reaction.</em>  TRUE. According to the Arrhenius equation, the lower the activation energy, the higher the rate constant, and the higher the rate of reaction. This is how catalysts act.

<em>d)It increased the activation energy of the reaction.</em> FALSE.

7 0
3 years ago
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