Answer:
125.5 ×10^-3 m^3= 0.1255 m^3
Explanation:
Volume=5.6mol×22.414dm^3
=125.5dm^3
Answer: Li is the reducing agentg and O is the oxidizing agent.
Explanation:
1) The oxidizing agent is the one that is reduced and the reducing agent is the one that is oxidized.
2) The given reaction is:
4Li(s) + O₂ (g) → 2 Li₂O(s)
3) Determine the oxidation states of each atom:
Li(s): oxidation state = 0 (since it is alone)
O₂ (g): oxidation state = 0 (since it is alone)
Li in Li₂O (s) +1
O in Li₂O -2
That because 2× (+1) - 2 = 0.
4) Determine the changes:
Li went from 0 to + 1, therefore it got oxidized and it is the reducing agent.
O went from 0 to - 2, therefore it got reduced and it is the oxidizing agent.
Answer:
Explanation:
Hello!!
Please remember that density=mass/volume.
In this case, we have the same mass for the feathers and the gold (1 pound).
So, if the mass is the same for both we have:
Df*Vg=Dg*Vf where f means feathers and g means gold.
In this case we see density is inversely related to volume. Both materials have the same mass. So which one have a bigger volume?
For this take a pound of feathers and submerge in a known volume of water. Note the displacement. Do the same for a pound of gold. Whichever has the smaller displacement, has the greater density.
In this case, Gold has the greatest density.
Answer:
Single replacement
Explanation:
Chemical equation:
2Al(NO₃)₃ + 3Ca → 3Ca(NO₃)₂ + 2Al
Single replacement:
It is the reaction in which one elements replace the other element in compound.
AB + C → AC + B
All other options are incorrect because,
Double replacement:
It is the reaction in which two compound exchange their ions and form new compounds.
AB + CD → AD +CB
Synthesis reaction:
It is the reaction in which two or more simple substance react to give one or more complex product.
Decomposition reaction:
It is the reaction in which one reactant is break down into two or more product.
AB → A + B
Combustion reaction:
Reaction in substance react with oxygen and form carbon dioxide and water.
Answer:
This is due to the physical properties of the sample, since it affects the volume dispensed.
Explanation:
For example, in the case of very dense samples, selected samples to adhere to the surface of the tip, dispensing more slowly. In contrast, ethanol samples are less viscous and more volatile and are dispensed more rapidly. Some of the ways to minimize these inconveniences are the use of ultra low retention pipette tips, since they have a hydrophobic plastic additive that prevents the liquid from adhering to the inside of the tip.
Another way is to use the reverse pipetting.
