The answer to your question is 61/99
1)
LHS = cot(a/2) - tan(a/2)
= (1 - tan^2(a/2))/tan(a/2)
= (2-sec^2(a/2))/tan(a/2)
= 2cot(a/2) - cosec(a/2)sec(a/2)
= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))
= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)
= 2[(1+cos(a) -1)/sin(a)]
=2cot a
= RHS
2.
LHS = cot(b/2) + tan(b/2)
= [1 + tan^2(b/2)]/tan(b/2)
= sec^2(b/2)/tan(b/2)
= 1/sin(b/2)cos(b/2)
using product to sums
= 2/sin(b)
= 2cosec(b)
= RHS
Answer:
148 degrees!
Step-by-step explanation:
They are 180 degrees together so just subtract 32. 180- 32 = 148.
Answer:
Total is 5 hours.
Step-by-step explanation:
... in the attached picture.
Hope this helps!
Choose me for brainliest please!!!
If you would like to solve (g ° f)(x), you can
calculate this using the following steps:<span>
(g ° f)(x) = g(f(x))
(g ° f)(x) = g(f(x)) = g(3x) = 2 * 3x = 6x
<span>The correct result would be 6x.</span></span>
