Answer: option D: 11/12
Explanation:
1) The sample space is formed by 36 pairs: 6×6 = 36.
2) Roolling 4 or more is the same that not rolling 3 or less
3) Rolling 3 or less are (1,1), (1,2), and (2,1). Those are 3 outcomes out of 36.
4) Therefore, not rolling 3 or less (the same that rolling 4 or more) has 36 - 3 = 33 outcomes out of 36.
5) The probability of 33 out of 36 is 33/36
6) Simplify the fraction 33/36 = 11/12
And that is the answer.
The two answers are the one selected and the choice |x-5| ≤ 1. The steps to solve the other equation are:
|x-5| ≤ 1
x-5 ≤ 1, x-5 ≥ 0
-(x-5) ≤ 6, x-5 is less than 0
x ≤ 6, x ≥ 5
x ≥ 4, x is less than 5
x ∈ [5,6]
x ∈ [4,5]
4 ≤ x ≤ 6
(^which was the original answer^)
Step-by-step explanation:
- 8-2x<u><</u><u> </u><u>5</u>
- -2x<u><</u>5-8
- x<u><</u><u> </u>-3/-2
- x<u><</u>1.5
hope it helps.
Answer:
X= 8
Y= 130
(8, 130)
Step-by-step explanation:
I used a graphing calculator to see where the two equations intersected.
Hope this helped :)
Answer:
Step-by-step explanation:
Let x represent the total number of stdents that has all grades in the school.
There are three grades in the school. One grade has 1/3 of the students, this means that number of students that belongs tho this grade is 1/3 × x = x/3
One grade has 1/4 of the students, this means that number of students that belongs to this grade is 1/4 × x = x/4
Total number of students in both grades would be x/3 +/x/4 = 7x/12
The number of students in the remaining grade would be
x - 7x/12 = 5x/12
fraction of students in the remaining grade would be
(5x/12)/x = 5/12
