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Alecsey [184]
2 years ago
10

M'(-5-4) is the image of M after a 90°

Mathematics
1 answer:
AleksAgata [21]2 years ago
6 0

Step-by-step explanation:

Let coordinate of M(x, y)

we know,

image of M(x,y)-------M'(-y,x)

From question

(-y,x)= (-5,-4)

or, -y = -5 and x= -4

So, y=5 and x= -4

Therefore M(x,y)=M(-4,5)

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m∠AOC = m∠AOB + m∠BOC

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