<h2>
The kinetic energy of boat (KE) = 25000 J or, 25 KJ</h2>
Explanation:
Given,
The mass of boat (m) = 2000 kg and
Speed (v) = 5.0
To find, the kinetic energy of boat (KE) = ?
We know that,
Kinetic energy =
=
= 1000 × 25 J
= 25000 J
= KJ [ ∵ 1 KJ = 1000 J]
= 25 KJ
∴ The kinetic energy of boat (KE) = 25000 J or, 25 KJ
Given the mass of R-134a m = 300kg; Volume of the container V = 9 cu. meter; Temperature of R-134a T = 10 degrees Celsius;
Formula of specific volume : v = V / m = 9 / 300 = 0.03 cu. m / kg.
At T = 10 degrees Celsius from saturated R-134a tables, vf = 0.0007930 cu. m /kg; vg = 0.049403 cu. m/kg. We know v = vf + x (vg - vf), so 0.03 = 0.0007930 + x (0.049403 - 0.0007930), which makes x = 0.601.
Specific enthalpy of R-134a in the container is h = hf + x*hfg = 65.43 + (0.601 * 190.73). Answer is 180.0587 kJ/kg
Waves travel away from the center of the wave, the center of the disturbance. Water is not being transported with the waves. The water will flow back into the pound. The surface was disturbed, but not the water.