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trasher [3.6K]
3 years ago
12

Alberto measures the length of a piece of wire to be 105 cm. The actual length of the wire was 120 cm. What was the percent erro

r of Alberto's measurement? Show your work. ​
Mathematics
1 answer:
natali 33 [55]3 years ago
7 0

Answer:

12.5%

Step-by-step explanation:

105 over 120 is the fraction that he got so you subtract 105 from 120 to get how much he missed. 120-105=15

He miscalculated by 15 cm out of the total of 120, 15/ 120

15/120=5/40=2.5/20 multiply the top and bottom by 5 to get the percentage out of 100. 2.5 times 5 =12.5, so he miscalculated by 12.5%

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3 years ago
Prove that the triangle EDF is isosceles. Give reasons for your answer.
Gekata [30.6K]

Answer:

\triangle EDF is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

\angle EDF = y

\text{External }\angle DFG = 90 +\dfrac{y}{2}

Let us try to find out \angle E and \angle DFE. After that we will compare them.

<u>Finding </u>\angle DFE<u>:</u>

Side EG is a straight line so \angle GFE = 180

\angle GFE is sum of internal \angle DFE and external \angle DFG

\angle GFE = 180 = \angle DFE  + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)

<u>Finding </u>\angle E<u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external \angle DFG = \angle E + \angle EDF

\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2}  -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)

Comparing equations (1) and (2):

It can be clearly seen that:

\angle DFE = \angle E =90-\dfrac{y}{2}

The two angles of \triangle EDF are equal hence \triangle EDF is isosceles.

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3 years ago
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Afina-wow [57]
The first one is B hope this helps
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3 years ago
A small motorboat travels 12mph in still water. It takes 2 hours longer to travel 46 miles going upstream than it does going dow
Natasha_Volkova [10]

Using the relation between velocity, distance and time, it is found that the rate of the current is of 3.33 mph.

<h3>What is the relation between velocity, distance and time?</h3>

Velocity is distance divided by time, hence:

v = d/t

A small motorboat travels 12mph in still water. With the current, upstream, 46 miles are traveled in t hours, hence:

12 + r = 46/t

r = 46/t - 12

Downstream, the time is of t + 2 hours, hence:

12 - r = 46/(t + 2)

r = 12 - 46/(t + 2)

Hence, equaling the values for r:

46/t - 12 = 12 - 46/(t + 2)

46/t + 46/(t + 2) = 24

\frac{46t + 92 + 46t}{t(t + 2)} = 24

92t + 92 = 24t² + 48t

24t² - 44t - 92 = 0

Using a quadratic equation calculator, the solution is t = 3. Hence the rate is found as follows:

r = 46/t - 12 = 46/3 - 12 = 3.33 mph.

More can be learned about the relation between velocity, distance and time at brainly.com/question/28155966

#SPJ1

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2 years ago
Which tool is not needed to construct a perpendicular bisector?
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A compass because youre just making two arcs
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Read 2 more answers
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