Answer:
<h3>The answer is 0.92 m/s²</h3>
Explanation:
To find the acceleration of an object given it's initial and final velocity and time taken we use the formula
where
v is the final velocity
u is the initial velocity
t is the time taken
a is the acceleration
From the question
v = 39 m/s
u = 27 m/s
t = 13 s
We have
We have the final answer as
<h3>0.92 m/s²</h3>
Hope this helps you
<span>The friction force ( µ . N ) must be enough to counter the gravity force ( m . g )
The Normal force from the rotating wall is the centripetal force = mv^2 / r
so with the lowest coefficient of friction ( 0.4 )
0.4 . v^2 / 2.5 = g
v^2 = 2.5 . 9.8 / 0.4
v = 7.83 m/s
T = 5Ď€ / 7.83 = 2.007 s
f = 0.5 Hz = 30 rpm</span>
1935.5 N is the "net force" acting on a car.
<u>Explanation</u>:
Given that,
Mass of the car is 790 kg.
Velocity of the car is 7 m/s. (v)
It turned around with 20 m. (r)
We know that, Net force = m × a
Now, Net force = m × a
Net force = 790 × 2.45
Net force = 1935.5 N