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bezimeni [28]
3 years ago
10

Why is it important to have a strong core (mid section)?

Physics
1 answer:
Reika [66]3 years ago
6 0

Answer:

Your core stabilizes your body, allowing you to move in any direction as well as having proper balance. It helps prevents falls and supports your body. So having a strong core is beneficial to everyone because it allows your body to function properly. Improved Balance and Stability.

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What is the velocity of a 12kg object that has the momentum of 60kgm/s?
Bad White [126]

Answer: 5 m/s

Explanation:

Momentum = mv (mass*velocity)

60kg*m/s = (12kg)*(v)

v = (60kg*m/s)/(12kg)

v = 5 m/s

4 0
3 years ago
there is a skier at the top of the ski slope the skier has potential energy what gives the skier her potential energy
scoundrel [369]

Her height on the mountain gives her the PE that she has.

She got it from the work that some person or machine did to lift her up there.

3 0
3 years ago
A charge q is at the point x = 5.0 m , y = 0. Write expressions for the unit vectors you would use in Coulomb's law if you were
Flauer [41]

Answer:

A) \^r = \^y

B) \^r = -\^x

C) \^r = -0.14\^x + 0.99\^y

Explanation:

Coulomb's Law is

\vec{F}_{ab} = K\frac{q_1q_2}{r^2}\^r

where r is the distance between the two point charges.

The question clearly asks the unit vector expressions of the force that q exerts on the other charge. So, we do not need to find the force, but only the distance vector, r, between charges, and then we can derive the unit vector pointing only the direction of the force.

A) \vec{r} = \vec{r}_b - \vec{r}_a = (5\^x + \^y) - (5\^x + 0) = \^y\\\^r = \frac{\vec{r}}{|\vec{r}|} = \frac{\^y}{1} = \^y

B) \vec{r} = \vec{r}_b - \vec{r}_a = (0 + 0) - (5\^x + 0) = -5\^x\\\^r = \frac{\vec{r}}{|\vec{r}|} = \frac{-5\^x}{5} = -\^x

C) \vec{r} = \vec{r}_b - \vec{r}_a = (4.5\^x + 3.5\^y) - (5\^x + 0) = -0.5\^x + 3.5\^y\\\^r = \frac{\vec{r}}{|\vec{r}|} = \frac{-0.5\^x + 3.5\^y}{\sqrt{(0.5)^2+(3.5)^2}} = \frac{-0.5\^x + 3.5\^y}{3.53} = -0.14\^x + 0.99\^y

7 0
3 years ago
Read 2 more answers
Can the momentum of an object change
OlgaM077 [116]
The answer for this is yes.
8 0
4 years ago
Read 2 more answers
A tank is 6 m long, 4 m wide, 5 m high, and contains kerosene with density 820 kg/m3 to a depth of 4.5 m. (Use 9.8 m/s2 for the
Mazyrski [523]

The pressure at the bottom of the tank is given by:

P = ρgh

P = pressure, ρ = fluid density, g = gravitational acceleration, h = depth

Given values:

ρ = 820kg/m³, g = 9.8m/s², h = 4.5m

Plug in and solve for P:

P = 820(9.8)(4.5)

P = 36000Pa

5 0
3 years ago
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