All categories

3 years ago

An atom bonds with another atom. What is the best classification for this reaction?

1 answer:

8 0

When an atom bonds another atom, the reaction that takes place is the combination reaction. The reaction will be A + B → AB, where AB is the combined product of the reactants A and B. An example is H2 + 1/2O2 → H2O

You might be interested in

Compare the gravitational acceleration on the following objects compared to the Sun using:

arsen [322]

The gravitational acceleration of White dwarf compared to Sun is 13,675.86.

The gravitational acceleration of Neutron star compared to Sun is 6.79 x 10⁻²⁴.

The gravitational acceleration of Star Betelgeuse compared to Sun is 8.5 x 10¹⁰.

<h3>Mass of the planets</h3>

Mass of sun = 2 x 10³⁰ kg

Mass of white dwarf = 2.765 x 10³⁰ kg

Mass of Neutron star = 5.5 x 10¹² kg

Mass of star Betelgeuse = 2.188 x 10³¹ kg

<h3>Radius of the planets</h3>

Radius of sun = 696,340 km

Radius of white dwarf = 7000 km

Radius of Neutron star = 11 km

Radius of star Betelgeuse = 617.1 x 10⁶ km

<h3>Gravitational acceleration of White dwarf compared to Sun</h3>

$\frac{g(star)}{g(sun)} = \frac{M(star)}{M(sun)} \times [\frac{R(sun)}{R(star)} ]^2\\\\\frac{g(star)}{g(sun)} = \frac{2.765 \times 10^{30}}{2\times 10^{30}} \times [\frac{696,340,000}{7,000,000} ]^2\\\\\frac{g(star)}{g(sun)} = 13,675.86$

<h3>Gravitational acceleration of Neutron star compared to Sun</h3>

$\frac{g(star)}{g(sun)} = \frac{M(star)}{M(sun)} \times [\frac{R(sun)}{R(star)} ]^2\\\\\frac{g(star)}{g(sun)} = \frac{5.5 \times 10^{12}}{2\times 10^{30}} \times [\frac{11,000}{7,000,000} ]^2\\\\\frac{g(star)}{g(sun)} = 6.79\times 10^{-24}$

<h3>Gravitational acceleration of Star Betelgeuse compared to Sun</h3>

$\frac{g(star)}{g(sun)} = \frac{M(star)}{M(sun)} \times [\frac{R(sun)}{R(star)} ]^2\\\\\frac{g(star)}{g(sun)} = \frac{2.188 \times 10^{31}}{2\times 10^{30}} \times [\frac{617.1 \times 10^9}{7,000,000} ]^2\\\\\frac{g(star)}{g(sun)} = 8.5\times 10 ^{10}$

Learn more about acceleration due to gravity here: brainly.com/question/88039

3 0

3 years ago

Calculate the mass of 1.35 moles of sodium chloride (NaCl).

Harlamova29_29 [7]

Answer:d

Explanation:

4 0

3 years ago

Each of three identical 15.0-L gas cylinders contains 7.50 mol of gas at 295 K. Cylinder A contains He, cylinder B contains O2,

Virty [35]

Answer:

Helium will have the highest average speed

Explanation:

the kinetic molecular theory tells us that the temperature of a gas is directly proportional to the average kinetic energy of the gas. So since all three gases have the same temperature, they must have the same kinetic energy. Kinetic energy is KE = 0.5mv². How then can a gas with such a small molar mass like helium have the same kinetic energy as much heavier gases like oxygen and sulphur dioxide? By having a much larger average speed

6 0

3 years ago

A penny rides on top of a piston as it undergoes vertical simple harmonic motion with an amplitude of 4.0cm. If the frequency is

nadezda [96]

Answer:

in the downward movement of the movement when the constant is lost

Explanation:

When the coin is on the piston it has a relationship given by

a = d²x / dt²

the piston position is

x = A cos wt

a = - A w² cos wt

the maximum acceleration is

a = - A w²

When the piston raises the acceleration of gravity and that of the piston go in the same direction, when the piston descends they relate it is contrary to gravity, therefore when the frequency increases, the point where the acceleration of the piston is greater than gravity arrives and the coin loses contact.

The point where you lose contact is

a = g

g = A w²

In short, in the downward movement of the movement when the constant is lost

7 0

3 years ago

One bright summer day a swimmer is floating with her head just above the surface of a large, clear lake where the water has inde

slavikrds [6]

Answer:

5.38035 m

Explanation:

$n_w$ = Refactive index of water = 1.43

h = Depth = 5.5 m

Critical angle is given by

$\theta_c=sin^{-1}\dfrac{1}{n_w}\\\Rightarrow \theta_c=sin^{-1}\dfrac{1}{1.43}\\\Rightarrow \theta_c=44.37^{\circ}$

d = horizontal distance from the post where she no longer see the bottom of wooden post

So,

$tan\theta_c=\dfrac{d}{h}\\\Rightarrow d=tan\theta_c\times h\\\Rightarrow d=tan44.37\times 5.5\\\Rightarrow d=5.38035\ m$

The distance d is 5.38035 m

4 0

3 years ago