Answer:
The reaction rate becomes quadruple.
Explanation:
According to the law of mass action:-
The rate of the reaction is directly proportional to the active concentration of the reactant which each are raised to the experimentally determined coefficients which are known as orders. The rate is determined by the slowest step in the reaction mechanics.
Order of in the mass action law is the coefficient which is raised to the active concentration of the reactants. It is experimentally determined and can be zero, positive negative or fractional.
The order of the whole reaction is the sum of the order of each reactant which is raised to its power in the rate law.
Thus,
Given that:- The rate law is:-
![r=k[A_2][B_2]](https://tex.z-dn.net/?f=r%3Dk%5BA_2%5D%5BB_2%5D)
Now, ![[A'_2]=2[A_2]](https://tex.z-dn.net/?f=%5BA%27_2%5D%3D2%5BA_2%5D)
and ![[B'_2]=2[B_2]](https://tex.z-dn.net/?f=%5BB%27_2%5D%3D2%5BB_2%5D)
So, ![r'=k[A'_2][B'_2]=k\times 2[A_2]\times 2[B_2]=4\times k[A_2][B_2]=4r](https://tex.z-dn.net/?f=r%27%3Dk%5BA%27_2%5D%5BB%27_2%5D%3Dk%5Ctimes%202%5BA_2%5D%5Ctimes%202%5BB_2%5D%3D4%5Ctimes%20k%5BA_2%5D%5BB_2%5D%3D4r)
<u>The reaction rate becomes quadruple.</u>
Answer:
A Horizon - The layer called topsoil; it is found below the O horizon and above the E horizon. Seeds germinate and plant roots grow in this dark-colored layer. It is made up of humus (decomposed organic matter) mixed with mineral particles.
Answer:
d. can be separated into components
it's the answer and i hope it helps you
When 12 moles of O₂ (g) react with C₃H₈O (g) then 8 moles of CO₂ (g) is produced. This is the chemical combustion reaction of propanol producing vapor of CO₂.
<h3>How to calculate the amount of CO₂ produced?</h3>
Alcohols undergo combustion reaction in the presence of oxygen gas to produce vapor of CO₂ and water.
In the given equation,
2 C₃H₈O (g) + 9 O₂ (g) → 6 CO₂ (g) + 8 H₂O (g)
To calculate the number of moles of CO₂ produced, first we have to balance the equation:
Divide the equation by 2
C₃H₈O (g) + 9/2 O₂ (g) → 3 CO₂ (g) + 4 H₂O (g)
Calculate the number of moles of CO₂ (g) produced with 1 mol of O₂ (g)
9/2 O₂ (g) → 3 CO₂ (g)
1 O₂ (g) → 3÷9/2 CO₂ (g) = 0.66 mol CO₂ (g)
For 12 mol of O₂ (g),
12 × 0.66 = 8 mol CO₂ (g)
Therefore, 8 mol of CO₂ (g) is produced from 12 mol of O₂ (g).
Learn more about Combustion reaction here:
brainly.com/question/14335621
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