Answer:
Partition coefficients are:
Chloroform-Water: 18.1
Diethyl ether-Water: 3.97
Benzene-Water: 1.71
You would choose chloroform to extract the compound
Explanation:
Partition coeffcient is defined as the ratio between solubility in g/mL of an organic compound and concentration of the solubility in an aqueous solution.
Solubility of the compound in the solvents is:
Water: 1g / 147.0mL = 6.80x10⁻³g/mL
Chloroform: 1g / 8.10mL = 0.123g/mL
Diethyl ether: 1g / 37.0mL = 0.0270g/mL
Benzene: 1g / 86.0mL = 0.0116g/mL
<h3>Partition coefficients are:</h3><h3>Chloroform-Water: 18.1</h3><h3>Diethyl ether-Water: 3.97</h3><h3>Benzene-Water: 1.71</h3><h3 />
The higher partition coefficient, the best extraction because the compound will have more affinity with this solvent in which the compound has the best solubillity.
Chloroform has the higher partition coefficient because has the higher solubility. That means chloroform is the solvent you would choose to extract the compound from an aqueous solution
A. They will Attract to each other
To calculate the number of molecules ch3cooh in a given amount of vinegar, we first need to determine the amount of ch3cooh in the solution by multiplying the percent <span>ch3cooh with the sample amount. Then, convert g to moles and use avogadro's number. We do as follows:
41.9 g vinegar solution ( .05 g </span><span>ch3cooh / g vinegar solution ) (1 mol / 60.05 g ) ( 6.022x10^23 g / 1 mol ) = 2.1x10^22 molecules </span><span>ch3cooh</span>
<u>Given:</u>
Dimensions of the room= 12 ft * 15 ft * 8.60 ft
<u>To determine:</u>
The amount of HCN that gives the lethal dose in the room with the given dimensions
<u>Explanation:</u>
As per the World Health Organization, the lethal dose of HCN is around 300 ppm
300 ppm = 300 mg of HCN/ kg of inhaled air
Volume of air = volume of room = 12 * 15 *8.6 = 1548 ft³
Now, 1 ft³ = 28316.8 cm³
Therefore, the calculated volume of air corresponds to:
1548 * 28316.8 = 4.383 * 10⁷ cm3
Density of air (at room temperature 25 C) = 0.00118 g/cm3
Thus mass of air corresponding to the calculated volume is
Mass = Density * volume = 0.00118 g/cm3 * 4.383 * 10⁷ cm3
= 5.172*10⁴ g = 51.72 kg
Lethal amount of HCN corresponding to 51.72 kg of air would be.
= 51.72 kg air* 300 mg of HCN/1 kg air = 15516 mg
Ans: Lethal dose of HCN = 15.5 g
Answer:
+5.7%
Explanation:
18.5mL/17.5mL = 1.057 = 105.7% - 100% = 5.7%
Since the measured volume was higher, it is PLUS 5.7%
