Answer : The mass of nitrous oxide formed from 85.20 g of nitrogen is, 133.9 grams.
Explanation :
As we are given that, 28.01 g of nitrogen is present in 44.01 g of nitrous oxide. Now we have to determine the mass of nitrous oxide formed from 85.20 g of nitrogen.
As, 28.01 g of nitrogen is present in 44.01 g of nitrous oxide
So, 85.20 g of nitrogen is present in 
of nitrous oxide
Thus, the mass of nitrous oxide formed from 85.20 g of nitrogen is, 133.9 grams.
Scientists often repeat one or more steps several times.
The balanced chemical reaction is expressed as:
<span>4hcl(g)+o2(g)→2h2o(l)+2cl2(g)
To determine the percent yield of the reaction, we need to calculate for the theoretical yield. This is the maximum amount of the product that can be produced from the reaction given the initial amounts of the reactants. First, we identify the limiting reactant as follows:
</span><span>63.1 g of hcl ( 1 mol / 36.46 g ) ( 1 mol O2 / 4 mol HCl) ( 32 g / mol) = 13.85 g O2
17.2 g of o2 ( 1 mol / 32 g ) ( 4 mol HCl / 1 mol O2) ( 36.46 g / mol) = 78.39 g HCl
Therefore, the limiting reactant would be HCl. We use the value for the HCl to calculate for the theoretical yield.
</span>63.1 g of hcl ( 1 mol / 36.46 g ) ( 2 mol Cl2 / 4 mol HCl) ( 70.9 g / mol ) = 61.35 g Cl2
Percent yield = actual / theoretical x 100
= 59.6 / 61.35 x 100
= 97.1%
C) Step 1: a horizontal spinning effect is formed from wind shear
Step 2: warm rising air shifts the horizontal rotation to a vertical rotation
Step 3: the vertical rotation expands and extends
