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Hitman42 [59]
2 years ago
9

The net of a square pyramid is shown

Mathematics
1 answer:
Wewaii [24]2 years ago
3 0

Answer:

Option (D)

Step-by-step explanation:

Surface area of a square pyramid is determined from the formula,

Surface area = Area of the square base + 4(Area of one lateral triangular side)

Area of the base = (Side)²

                            = 8²

                            = 64 cm²

Area of one lateral triangle = \frac{1}{2}(\text{Base})(\text{Height})

                                             = \frac{1}{2}(8)(8)

                                             = 32 cm²

Therefore, surface area of the square pyramid = 64 + 4(32)

                                                                              = 64 + 128

                                                                              = 192 cm²

Therefore, Option (D) will be the correct option.

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Answer:

g ÷ 5

Step-by-step explanation:

Variable: g

Operation: Division (represented as ÷)

Constant: 5

Put together the equation:

g ÷ 5

Hope this helps :)

5 0
3 years ago
3(x+1)-5=3x-2<br><br> Option1: no solution<br> Option2:infinite solutions<br> Option3:one solution
Vikentia [17]

Answer:

Simplify 3(x+1)−5.

3x−2=3x−2

Move all terms containing x to the left side of the equation.

−2=−2 Since −2=−2 , the equation will always be true for any value of x

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

(−∞,∞)

Option2 : infinite solutions

Step-by-step explanation:

3 0
3 years ago
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How do you solve X-y=11 by elimination
Verdich [7]

Answer: x=y+11

Step-by-step explanation:

Equation: x−y=11

Step 1. You need to add y to both sides.

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x=y+11

3 0
3 years ago
A The length of a rectangle is 4 m more
Lady bird [3.3K]

Given :

  • The length of a rectangle is 4m more than the width.
  • The area of the rectangle is 45m²

⠀

To Find :

  • The length and width of the rectangle.

⠀

Solution :

We know that,

\qquad { \pmb{ \bf{Length \times Width = Area_{(rectangle)}}}}\:

So,

Let's assume the length of the rectangle as x and the width will be (x – 4).

⠀

Now, Substituting the given values in the formula :

\qquad \sf \: { \dashrightarrow x  \times  (x - 4) = 45 }

\qquad \sf \: { \dashrightarrow {x}^{2}  - 4x = 45 }

\qquad \sf \: { \dashrightarrow {x}^{2}  - 4x - 45 = 0 }

\qquad \sf \: { \dashrightarrow {x}^{2}    - 9x+ 5 x - 45 = 0 }

\qquad \sf \: { \dashrightarrow x(x - 9) + 5(x - 9) = 0 }

\qquad \sf \: { \dashrightarrow (x  - 9) (x  + 5) = 0 }

\qquad \sf \: { \dashrightarrow x = 9, \: \: x =  - 5}

⠀

Since, The length can't be negative, so the length will be 9 which is positive.

⠀

\qquad { \pmb{ \bf{ Length _{(rectangle)} = 9\:m}}}\:

\qquad { \pmb{ \bf{ Width _{(rectangle)} = 9 - 4=5\: m}}}\:

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

8 0
2 years ago
Use substitution method &amp; show your work.<br>y = x^2 + 3x - 1<br>4x + 1 = y
irina1246 [14]
4x + 1 = x^2 + 3x - 1
4x = x^2 + 3x - 2
0 = x^2 -x - 2
0 = x^2 -x + 1 - 3
0 = (x - 1)^2 - 3
3 = (x - 1)^2
sqrt 3=(x-1) and (-(x-1))
x = 1+sqrt 3 and 1-sqrt 3
sqrt means square root
7 0
3 years ago
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