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Tresset [83]
3 years ago
9

I’m too lazy to do it so if someone can do it it would mean a lot

Mathematics
2 answers:
kvv77 [185]3 years ago
6 0

Answer: I think it would 2/15 so C positive

Step-by-step explanation:

Dafna11 [192]3 years ago
5 0

Answer:

a

Step-by-step explanation:

did the math :)

brainliest pls!

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A block is set in motion hanging from a spring and oscillates about its resting position
coldgirl [10]

Answer:

t = 1.277 sec and t = 2.848 sec

Step-by-step explanation:

This problem is much more easily done by graphing it than by computing it using algebra.

The values of t we're looking for are the ones that make x = 0, so we want the solutions of 0.6sin(2t)+0.4cos(2t)=0 on the interval [0, 3].

According to the graph, this is true when t = 1.277 seconds and t = 2.848 seconds.

8 0
3 years ago
Read 2 more answers
Can someone help me please i need help..! problem: x/-8+15>23
bazaltina [42]

Answer:

X<-64

Step-by-step explanation:

3 0
2 years ago
Find the circumference of a circle with a radius of 2 inches. Give an exact answer.
pychu [463]

Answer:C=2πr=2·π·2≈12.56637in

Step-by-step explanation:

4 0
3 years ago
2x^4–5x^3+x^2+3x+2=?<br><br> X=5
DanielleElmas [232]

Answer:

2x^4–5x^3+x^2+3x+2=

2 \times 5^4–5 \times 5^3+5^2+3 \times 5+2

= 2 × 625 – 5 × 125 + 25 + 3 × 5 + 2

=1250 – 625 + 25 + 15 +2

= 1292 – 625

= 667

3 0
2 years ago
Find the volume of the wedge cut from the first octant by the cylinder z=12-3y^2 and the plane x+y=2.
LuckyWell [14K]

Answer:

The wedge cut from the first octant ⟹ z ≥ 0 and y ≥ 0 ⟹ 12−3y^2 ≥ 0 ⟹ 0 ≤ y ≤ 2  

0 ≤ y ≤ 2 and x = 2-y ⟹ 0 ≤ x ≤ 2  

V = ∫∫∫ dzdydx  

dz has changed from zero to 12−3y^2  

dy has changed from zero to 2-x  

dx has changed from zero to 2  

V = ∫∫∫ dzdydx = ∫∫ (12−3y^2) dydx = ∫ 12(2-x)-(2-x)^3 dx =  

24(2)-6(2)^2+(2-2)^4/4 -(2-0)^4/4 = 20

Step-by-step explanation:

8 0
3 years ago
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