From the ohms law, the current through a conductor is directly proportional to the potential difference. Thus we get the equation I = V/R
where I is the current in Ampheres, V is the voltage in volts and R is the resistance in Ohms.
Hence; I = 3/12
= 0.25 Ampheres
Thus, the current through the flashlight is 0.25 Ampheres
Complete question
The diagram for this question is shown on the first uploaded image
Answer:
The largest possible distance is 
Explanation:
From the question we are told that
The separation between Speaker at position A and B is AB = 6.60 m
The frequency of the tune which the speaker are playing is 
The speed of sound is 
Generally the wavelength of the tune playing is mathematically represented as

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Let the observer be at position D
Generally the distance A and is mathematically evaluated using Pythagoras theorem as

Let BC = e
So

Generally the path difference between the first and the second speaker from the observer point of view is mathematically represented as

=> 
Generally the condition for destructive interference is mathematically represented as

Here n is the order of the fringe which is one
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Your list of statements doesn't have any true ones.
-- (2 square root of 7) and (square root of 28) are both the same number.
-- So if you do that subtraction, the difference is zero.
To answer the question above, we make use of the equation,
Work = Power x time
From the equation, time may be solved through
time = Work / Power
Substituting the known values from the given,
time = (5700 J) / (750 J/s)
= 7.6 s
Answer:
<h2>option b , 2A</h2>
Explanation:
<h2>V= IR</h2>
thus
<h2>I=V/R</h2>
so putting values we get,
I = 120/ R
for the value of R...
R(series) = R1 + R2 + R3
R= 20 + 20+ 20 = 60 ohm
<h2>R=60ohm</h2>
thus, I=120/60 = 2
Therefore,
<h2>I = 2A</h2>