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jek_recluse [69]

3 years ago

7

A charge Q exerts a 1.2 N force on another charge q. If the distance between the charges is doubled, what is the magnitude of th

e force exerted on Q by q

1 answer:

Anon25 [30]3 years ago

8 0

Answer:

0.3 N

Explanation:

Electromagnetic force is F= Kq1q2/r^2, where r is the distance between charges. If r is doubled then the force will be 1/4F which is 0.3 N.

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Answer:

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we clear the specific heat of the metal

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