A charge Q exerts a 1.2 N force on another charge q. If the distance between the charges is doubled, what is the magnitude of th
e force exerted on Q by q
1 answer:
Answer:
0.3 N
Explanation:
Electromagnetic force is F= Kq1q2/r^2, where r is the distance between charges. If r is doubled then the force will be 1/4F which is 0.3 N.
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