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gogolik [260]
2 years ago
9

PLEASE HELP!!!I NEED IT

Mathematics
1 answer:
SVEN [57.7K]2 years ago
7 0

Answer:

10. y = 49, x = 15

11. y = 4, x = 61

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Solve each equation by factoring,<br>x² - 2x - 15 = 0​
valina [46]

Answer:

x=−3 or x=5

Step-by-step explanation:

x2−2x−15=0

Step 1: Factor left side of equation.

(x+3)(x−5)=0

Step 2: Set factors equal to 0.

x+3=0 or x−5=0

x=−3 or x=5

7 0
3 years ago
What is the base 8 representation of 112
Andreas93 [3]
Solution Step1 Converting 112 to base 10.
1*82=64
1*81=8
2*80=2
Adding all to get Ans=7410 <span>Step2 converting 7410 to 2</span> The equation calculation formula for 7410 number to 2 is like this below.
2|74 
2|37|0
2|18|1
2|9|0
2|4|1
2|2|0
2|1|0
2|1|1
<span>Ans:10010102</span> 

3 0
3 years ago
Read 2 more answers
A circle has a sector with area 24/5pi and central angle of 48°. What is the area of the circle? Either enter an exact answer in
ra1l [238]

Answer:

Area_circle = pi*(24/5)*(360/48)=36pi = 113.097

5 0
3 years ago
In a large population of college-educated adults, the mean IQ is 118 with a standard deviation of 20. Suppose 200 adults from th
cricket20 [7]

Answer: 0.0793

Step-by-step explanation:

Let the IQ of the educated adults be X then;

Assume X follows a normal distribution with mean 118 and standard deviation of 20.

This is a sampling question with sample size, n =200

To find the probability that the sample mean IQ is greater than 120:

P(X > 120) = 1 - P(X < 120)

Standardize the mean IQ using the sampling formula : Z = (X - μ) / σ/sqrt n

Where;  X = sample mean IQ; μ =population mean IQ; σ = population standard deviation and n = sample size

Therefore, P(X>120) = 1 - P(Z < (120 - 118)/20/sqrt 200)

                                 = 1 - P(Z< 1.41)

The P(Z<1.41) can then be obtained from the Z tables and the value is 0.9207

Thus; P(X< 120) = 1 - 0.9207

                          = 0.0793

3 0
3 years ago
Find a,b,c and d?..........
cupoosta [38]

9514 1404 393

Answer:

  a = 6, b = 12, c = 6, d = 6√3

Step-by-step explanation:

The two triangles are the "special" triangles.

The 45-45-90 triangle has side lengths in the ratios 1 : 1 : √2.

The 30-60-90 triangle has side lengths in the ratios 1 : √3 : 2.

Then ...

  c : a : 6√2 = 1 : 1 : √2   ⇒   c = a = 6

and ...

  a : d : b = 1 : √3 : 2   ⇒   d = 6√3 and b = 12 . . . (since a=6)

The lengths are ...

  a = 6, b = 12, c = 6, d = 6√3

4 0
2 years ago
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