Solve the proportion below.

Mathematics

1 answer:

raketka [301]3 years ago

7 0

Answer:

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PLSSSSSSSSSSSSSSSSSSSSSSSS HELP ME!!

zzz [600]

Answer:

For the top table:

[x] | 3.1 | 2.5 | 1.2 | 0.9 | 0.14 | 0.06 | 0.02 |

[y] | 15.5 | 12.5 | 6 | 4.5 | 0.7 | 0.3 | 0.1 |

For the bottom table:

k = 5

[x] | 3.1 | 2.5 | 1.2 | 0.9 | 0.14 | 0.06 | 0.02 |

[y] | 15.5 | 12.5 | 6 | 4.5 | 0.7 | 0.3 | 0.1 |

3 0

3 years ago

Find the value of the constant m √150 - √12m + √54 = 0

Tomtit [17]

Answer:

m is √2

Step-by-step explanation:

${ \tt{ \sqrt{150} - \sqrt{12}m + \sqrt{54} = 0 }} \\ { \tt{ \sqrt{12}m } = \sqrt{150} - \sqrt{54} } \\ { \tt{ (\sqrt{4 \times 3}) m = ( \sqrt{25 \times 6} ) - ( \sqrt{9 \times 6}) }} \\ { \tt{( \sqrt{4 \times 3} )m = 5 \sqrt{6} - 3 \sqrt{6} }} \\ { \tt{2 \sqrt{3}m = 5 \sqrt{6} - 3 \sqrt{6} }} \\ { \tt{2 \sqrt{3} m = 2 \sqrt{6} }} \\ { \tt{ \sqrt{3} m = \sqrt{6} }} \\ { \tt{ \sqrt{3} m = ( \sqrt{3} \times \sqrt{2} ) }} \\ { \tt{m = \sqrt{2} }}$