Answer:
x = -13, y = -3
Step-by-step explanation:
let a number = x; the other = y
x = 3y - 4
x + y = -16
Isolate the y in the second equation. Subtract x from both sides
x (-x) + y = -16 (-x)
y = -16 - x
Plug in -16 - x for y
x = 3(-16 - x) - 4
Simplify. Distribute 3 to all terms within the parenthesis
x = -3x - 48 - 4
x = -3x - 52
Isolate the x. Add 3x to both sides
x (+3x) = -3x (+3x) - 52
4x = -52
Divide 4 from both sides
(4x)/4 = (-52)/4
x = -52/4
x = -13
Plug in -13 for x in one of the equations:
x + y = -16
(-13) + y = -16
Isolate the x. Add 13 to both sides
y - 13 (+13) = -16 (+13)
y = -16 + 13
y = -3
Answers: x = -13, y = -3
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1 out of 7. cause there are 7 socks and 1 black sock. nit sure tho
Answer:
X = 14
Step-by-step explanation:
A jump discontinuity occurs when the limits as x approaches a number from the left and right are not equal. Basically, the graph "jumps" from one number to another at that x value.
A point discontinuity occurs when limits as x approaches a number from the left and right are equal, but the actual value of f(x) at x is not equal to the limit. Basically, a point is missing and there is a "hole" in the graph at that x value.
Looking at your graph, you can see that at x=0, the graph "jumps" from a value of 2 as the graph approaches x=0 from the left to a value of 1 as the graph approaches x=0 from the right. That means there is a jump discontinuity at x=0.
You can also see that there is a "hole" in the graph at x=-2 and x=8 as seen by the open circle. There is no hole at x=3 because the circle is filled in. That means there is a point discontinuity at x=-2 and x=8.
Your answer is B) jump discontinuity at x=0; point discontinuities at x=-2 and x=8.
Answer:
6x^2 + 11x -1
Step-by-step explanation:
4x^2 + 9x + 2 + 2x^2 + 2x -3
Add the like terms to get the answer
