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olya-2409 [2.1K]
3 years ago
9

What is the square root of x over the square root of x to the 1/4 power

Mathematics
1 answer:
denis23 [38]3 years ago
5 0
4 as the denominator of the fraction is equal to the degree of the root so the answer is the 4th root of x\sqrt[4]{x}
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How can you simplify 24 to 96 ​
Nezavi [6.7K]

Step-by-step explanation:

Reduce 24/96 to lowest terms

Find the GCD (or HCF) of numerator and denominator. GCD of 24 and 96 is 24.

24 ÷ 2496 ÷ 24.

Reduced fraction: 14. Therefore, 24/96 simplified to lowest terms is 1/4.

7 0
3 years ago
Read 2 more answers
Leonard's parents told him that he can only play video games for less than 5 1/2 hours each week. Leonard has a new game and he
Natasha2012 [34]
The correct answer should be 7 levels for the entirety of the week. However, there are two solutions that satisfy this question so perhaps it is really asking how many additional levels he is able to beat. In this case, the answer should be B: x > 5 2/3
8 0
3 years ago
Read 2 more answers
Max makes and sells posters. The function p(x)= -10x^2 +200x -250, graphed below, indicates how much profit he makes in a month
viktelen [127]
Here is our profit as a function of # of posters
p(x) =-10x² + 200x - 250
Here is our price per poster, as a function of the # of posters:
pr(x) = 20 - x
Since we want to find the optimum price and # of posters, let's plug our price function into our profit function, to find the optimum x, and then use that to find the optimum price:
p(x) = -10 (20-x)² + 200 (20 - x) - 250
p(x) = -10 (400 -40x + x²) + 4000 - 200x - 250
Take a look at our profit function. It is a normal trinomial square, with a negative sign on the squared term. This means the curve is a downward facing parabola, so our profit maximum will be the top of the curve.
By taking the derivative, we can find where p'(x) = 0 (where the slope of p(x) equals 0), to see where the top of profit function is.
p(x) = -4000 +400x -10x² + 4000 -200x -250
p'(x) = 400 - 20x -200
0 = 200 - 20x
20x = 200
x = 10                         
p'(x) = 0 at x=10. This is the peak of our profit function. To find the price per poster, plug x=10 into our price function:
price = 20 - x
price = 10
Now plug x=10 into our original profit function in order to find our maximum profit:
<span>p(x)= -10x^2 +200x -250
p(x) = -10 (10)</span>² +200 (10) - 250
<span>p(x) = -1000 + 2000 - 250
p(x) = 750

Correct answer is C)
</span>
7 0
3 years ago
Suppose that demand in period 1 was 7 units and the demand in period 2 was 9 units. Assume that the forecast for period 1 was fo
Zepler [3.9K]

Answer:

Step-by-step explanation:

Forecast for period 1 is 5

Demand For Period 1 is 7

Demand for Period  2 is 9  

Forecast  can be given by

F_{t+1}=F_t+\alpha (D_t-F_t)

where

F_{t+1}=Future Forecast

F_t=Present\ Period\ Forecast

D_t=Present\ Period\ Demand

\alpha =smoothing\ constant  

F_{t+1}=5+0.2(7-5)

F_{t+1}=5.4

Forecast for Period 3

F_{t+2}=F_{t+1}+\alpha (D_{t+1}-F_{t+1})

F_{t+2}=5.4+0.2\cdot (9-5.4)

F_{t+2}=6.12  

8 0
3 years ago
A farmer sells 8.8 kilograms of apples and pears at the farmer's market. 3 /4 of this weight is apples, and the rest is pears. H
gayaneshka [121]

Answer:

  2.2 kg

Step-by-step explanation:

If 3/4 of the weight is apples, the remaining 1/4 is pears. 1/4 of 8.8 is 2.2, so ...

  the farmer sold 2.2 kg of pears at the farmer's market.

3 0
3 years ago
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