Step-by-step explanation:
Reduce 24/96 to lowest terms
Find the GCD (or HCF) of numerator and denominator. GCD of 24 and 96 is 24.
24 ÷ 2496 ÷ 24.
Reduced fraction: 14. Therefore, 24/96 simplified to lowest terms is 1/4.
The correct answer should be 7 levels for the entirety of the week. However, there are two solutions that satisfy this question so perhaps it is really asking how many additional levels he is able to beat. In this case, the answer should be B: x > 5 2/3
Here is our profit as a function of # of posters
p(x) =-10x² + 200x - 250
Here is our price per poster, as a function of the # of posters:
pr(x) = 20 - x
Since we want to find the optimum price and # of posters, let's plug our price function into our profit function, to find the optimum x, and then use that to find the optimum price:
p(x) = -10 (20-x)² + 200 (20 - x) - 250
p(x) = -10 (400 -40x + x²) + 4000 - 200x - 250
Take a look at our profit function. It is a normal trinomial square, with a negative sign on the squared term. This means the curve is a downward facing parabola, so our profit maximum will be the top of the curve.
By taking the derivative, we can find where p'(x) = 0 (where the slope of p(x) equals 0), to see where the top of profit function is.
p(x) = -4000 +400x -10x² + 4000 -200x -250
p'(x) = 400 - 20x -200
0 = 200 - 20x
20x = 200
x = 10
p'(x) = 0 at x=10. This is the peak of our profit function. To find the price per poster, plug x=10 into our price function:
price = 20 - x
price = 10
Now plug x=10 into our original profit function in order to find our maximum profit:
<span>p(x)= -10x^2 +200x -250
p(x) = -10 (10)</span>² +200 (10) - 250
<span>p(x) = -1000 + 2000 - 250
p(x) = 750
Correct answer is C)</span>
Answer:
Step-by-step explanation:
Forecast for period 1 is 5
Demand For Period 1 is 7
Demand for Period 2 is 9
Forecast can be given by

where





Forecast for Period 3


Answer:
2.2 kg
Step-by-step explanation:
If 3/4 of the weight is apples, the remaining 1/4 is pears. 1/4 of 8.8 is 2.2, so ...
the farmer sold 2.2 kg of pears at the farmer's market.