Hey
Sorry, But There Is No 7th Element in group two. only six which is Radium.
~Spades15
Answer:

Explanation:
1. Given that,
Initial speed of a bicycle, u = 4 m/s
The final speed of a bicycle, v = 6 m/s
Time, t = 6 s
We need to find the acceleration of the bicycle. We know that, acceleration is equal to the change in speed divided by time taken. So,

So, the acceleration of the bicycle is equal to
.
Answer:
The net ionic equation for the given reaction :

Explanation:
...[1]
..[2]
...[3]

Replacing
, NaI and
in [1] by usig [2] [3] and [4]

Removing the common ions present ion both the sides, we get the net ionic equation for the given reaction [1]:

B Very Acidic llllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllll
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