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tresset_1 [31]
3 years ago
9

Which analogy can best be likened to the activation energy of a chemical reaction? a drain through which water flows a slide dow

n which a child descends a hill over which a wagon is pushed an alley down which a bowling ball is rolled?
Chemistry
2 answers:
Nina [5.8K]3 years ago
7 0
Answer is: <span>a hill over which a wagon is pushed.
</span>For all chemical reaction some energy is required and that energy is called activation energy (<span>energy that needs to be absorbed for a chemical reaction to start)<span>.
There are two types of reaction: endothermic reaction (chemical reaction that absorbs more energy than it releases) and exothermic reaction (chemical reaction that releases more energy than it absorbs).
</span></span>R<span>eactions occur faster with a catalyst because they require less activation energy.</span>
statuscvo [17]3 years ago
4 0

The correct answer is a hill over which a wagon is pushed

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Th e enzyme-catalyzed conversion of a substrate at 25°C has a Michaelis constant of 0.045 mol dm−3. Th e rate of the reaction is
Elis [28]

Answer:

1.620\times 10^{-3} mol/dm^3 sis the maximum velocity of this reaction.

Explanation:

Michaelis–Menten 's equation:

v=V_{max}\times \frac{[S]}{K_m+[S]}=k_{cat}[E_o]\times \frac{[S]}{K_m+[S]}

V_{max}=k_{cat}[E_o]

v = rate of formation of products =

[S] = Concatenation of substrate

[K_m] = Michaelis constant

V_{max} = Maximum rate achieved

k_{cat} = Catalytic rate of the system

[E_o] = Initial concentration of enzyme

We have :

K_m=0.045 mol/dm^3

v=1.15 mmol/dm^3 s=1.15\times 10^{-3} mol/dm^3 s

[S]=0.110 mol/dm^3

v=V_{max}\times \frac{[S]}{K_m+[S]}

1.15\times 10^{-3} mol/dm^3 s=V_{max}\times \frac{0.110 mol/dm^3}{[(0.045 mol/dm^3)+(0.110 mol/dm^3)]}

V_{max}=\frac{1.15\times 10^{-3} mol/dm^3 s\times [(0.045 mol/dm^3)+(0.110 mol/dm^3)]}{0.110 mol/dm^3}=1.620\times 10^{-3} mol/dm^3 s

1.620\times 10^{-3} mol/dm^3 sis the maximum velocity of this reaction.

8 0
3 years ago
How much silver can be produced from 125g of Ag2S
rosijanka [135]

Answer:

108.9g of Silver can be produced from 125g of Ag2S

Explanation:

The compound Ag2S shows that two atoms of Silver Ag, combined with an atom of Sulphur S to form Ag2S. We can as well say the combination ration of Silver to Sulphur is 2:1

•Now we need to calculate the molecular weight of this compound by summing up the molar masses of each element in the compound.

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•Molar mass of Sulphur S= 32g/mol

•Molecular weight of Ag2S= (2×107.9g/mol) + 32g/mol

•Molecular weight of Ag2S= 215.8g/mol + 32g/mol= 247.8g/mol

•From our calculations, we know that 215.8g/mol of Ag is present in 247.8g/mol of Ag2S

If 247.8g Ag2S produced 215.8g Ag

125g Ag2S will produce xg Ag

cross multiplying we have

xg= 215.8g × 125g / 247.8g

xg= 26975g/247.8

xg= 108.85g

Therefore, 108.9g of Silver can be produced from 125g of Ag2S

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