Explanation:
Ionic compounds are the compounds in which complete transfer of electrons takes place from one element to another. In these compounds, the forces of attraction between the particles is strong and hence, they have the highest boiling points.
Answer:
Percent yield = 89.1%
Explanation:
Based on the equation:
Cl₂ + 2KI → 2KCl + I₂
<em>1 mole of Cl₂ reacts with 2 moles of KI to produce to moles of KCl</em>
<em />
To solve this quesiton we must find the moles of each reactant in order to find the limiting reactant. With the limiting reactant we can find the moles of KCl and the mass:
<em>Moles Cl₂:</em>
8x10²⁵ molecules * (1mol / 6.022x10²³ molecules) = 133 moles
<em>Moles KI -Molar mass: 166.0028g/mol-</em>
25g * (1mol / 166.0028g) = 0.15 moles
Here, clarely, the KI is the limiting reactant
As 2 moles of KI produce 2 moles of KCl, the moles of KCl produced are 0.15 moles. The theoretical mass is:
0.15 moles * (74.5513g / mol) =
11.2g KCl
Percent yield is: Actual yield (10.0g) / Theoretical yield (11.2g) * 100
<h3>Percent yield = 89.1%</h3>
35g Mg x 1mol / 24g = 840 mol
The specific heat capacity of the metal is determined as 0.76 J/g⁰C.
<h3>Mass of the water</h3>
mass = density x volume
mass = 342 ml x 1 g/ml = 342 g
<h3>Specific heat capacity of the metal</h3>
Apply the law of conservation of energy;
Heat lost by the metal = Heat gained by the calorimeter + heat gained by water
(93.4)(85 - 29.3)c = (8.29)(29.3) + (342)(4.186)(29.3 - 26.7)
5,202.38c = 3,965.088
c = 3,965.088/5,202.38
c = 0.76 J/g⁰C
Thus, the specific heat capacity of the metal is determined as 0.76 J/g⁰C.
The complete question is below;
93.4 g of a metal is heated to 85.0 C in a hot water bath, then dropped into a calorimeter containing 342 ml of water (d 1.00 g/mL) at 26.7 . The equilibrium temperature was found to be 29.3 C. Calculate the specific heat of the metal with proper units. (C.cal 8.29 J/c)
Learn more about specific heat capacity here: brainly.com/question/16559442
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