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Maslowich
3 years ago
8

The process of cellular respiration occurs in

Chemistry
1 answer:
EleoNora [17]3 years ago
7 0

Answer: plants and animal cells

Explanation:

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The thermite reaction, in which powdered aluminum reacts with iron oxide, is highly exothermic: 2Al(s) + F e2O3 (s)→A l2O 3 (s) 
bija089 [108]
For this problem, we use the Hess' Law.

ΔHrxn = ∑(ν*Hf of products) - ∑(ν*Hf of reactants)

The ν represents the corresponding stoichiometric coefficients of the substances, while Hf is the heat of formation. For pure elements, Hf = 0.

Hf of Al₂O₃ = <span>−1676.4 kJ/mol
</span>Hf of Fe₂O₃ = <span>-826.0 kJ/mol

Thus,

</span>ΔHrxn = 1*−1676.4 kJ/mol + 1*-826.0 kJ/mol
<em>ΔHrxn = -2502.4 kJ/mol</em>
4 0
3 years ago
1. Criminal profiling assigns crimes as one of two kinds. If a criminal profiler was looking at a case that involved a sophistic
amm1812

Answer:

So, for 1 I am most certain it has to be Organized so C. And for 2 that would be true if my brain isn't failing me- I hope this helps!

Explanation:

4 0
3 years ago
Read 2 more answers
When would a cell use Active Transport? Mark all that apply.
Jobisdone [24]

Answer:

Option B, When the cell needs to move a compound against its concentration gradient.

Explanation:

A cell uses active transport when it has to transport substances against the concentration gradient across its membrane.

In active transport additional energy is used (generally provided by energy molecules like ATP) to push the substance across any membrane from low concentration side  to high concentration side.

Option B is correct

6 0
3 years ago
a sample of compound determined to contain 1.71 g C and 0.287 g H. The corresponding empirical formula is
fiasKO [112]

Answer: The empirical formula is CH_2.

Explanation:

Mass of C = 1.71 g

Mass of H = 0.287 g

Step 1 : convert given masses into moles.

Moles of C = \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{1.71g}{12g/mole}=0.142moles

Moles of H = \frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.287g}{1g/mole}=0.287moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =\frac{0.142}{0.142}=1

For H =\frac{0.287}{0.142}=2

The ratio of C: H = 1: 2

Hence the empirical formula is CH_2.

4 0
3 years ago
How is matter classified?
pshichka [43]
Matter is classified into two groups: Pure Substances and Mixtures.
5 0
3 years ago
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