Answer:
The new pressure is 53.3 kPa
Explanation:
This problem can be solved by this law. when the volume remains constant, pressure changes directly proportional as the Aboslute T° is modified.
T° increase → Pressure increase
T° decrease → Pressure decrease
In this case, temperature was really decreased. So the pressure must be lower.
P₁ / T₁ = P₂ / T₂
80 kPa / 300K = P₂/200K
(80 kPa / 300K) . 200 K = P₂ → 53.3 kPa
Answer:
Its single - displacement.
Explanation:
Answer:
26.5 g
Explanation:
First we convert 100.0 mL to L:
- 100.0 mL / 1000 = 0.100 L
Now we <u>calculate how many moles of sodium carbonate are needed</u>, using the <em>definition of molarity</em>:
- Molarity = moles / liters
- moles = molarity * liters
- 2.5 M * 0.100 L = 0.25 mol
Finally we <u>convert 0.25 moles of sodium carbonate into grams</u>, using its <em>molar mass</em>:
- 0.25 mol * 106 g/mol = 26.5 g
Answer:
See explanation
Explanation:
The reaction equation is;
C3H8 (g) + 5O2(g) -------> 4H2O(g) + 3CO2(g)
From the formula;
Total enthalpy of reactants = (ΔHf of Reactant 1 x Coefficient) + (ΔHf of Reactant 2 x Coefficient)
Total enthalpy of products= (ΔHf of Product 1 x Coefficient) + (ΔHf of Product 2 x Coefficient)
Hence;
Total enthalpy of reactants =[(-103.85 * 1) + (0 * 5)] = -103.85 + 0 = -103.85 KJ/mol
Total enthalpy of products= [(-393.51 * 4) +(-241.82 * 3)] = (-1574.04) + (-483.64) = -2057.68 KJ/mol
