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deff fn [24]
3 years ago
8

20. What is the transformation?:

Mathematics
2 answers:
schepotkina [342]3 years ago
8 0

Answer:

Reflection

Step-by-step explanation:

A rotation would be to rotate a figure around the origin

A reflection would be to reflect the figure around one of the axes.

A translation would be to move a figure a certain amount of units.

Since A and A' are 2 units away from the y-axis, and C, B, B', and C' are all one unit away from the y-axis, this could not be a translation because the position of A'B'C' is not the same position of ABC.

It could not be a rotation around the origin or any point because it would result the figure in either Quadrant 2 or 3, and in the one occasion it would be in Quadrant 1, the figure cannot be in that position.

This reveals only one option, that which is a reflection. A reflection about the x-axis would not make sense, since it would result in Quadrant 3, so a reflection around the y-axis would make the most sense.

The data we have above also accounts for a reflection, since all points are a certain distant away from the y-axis.

zheka24 [161]3 years ago
7 0
Reflection ,, it just made a copy of the shape on the other side , it’s identical which means it’s a reflection
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How do i add and subtract polynomials?<br>(4v-6v)-(v-5v^3)+(5v^3+4)
Ksenya-84 [330]
Distribute and add like terms and you are good

alirghty

we can make it easier by simplifying what we can

(4v-6v)=-2v so

(-2v)-1(v-5v³)+(5v³+3)=
-2v-v+5v³+5v³+3=
10v³-3v+3
7 0
3 years ago
10. Explain why log328 is between 3 and 4.
maw [93]

Answer:

See explanation.

(Before continuing reading, I took the base to be 3. Please tell me if you didn't want the base to be 3.)

Step-by-step explanation:

I assume 3 is suppose to be the base. Let's list some values that can be written as 3 to some integer.

3^0=1

3^1=3

3^2=9

3^3=27

3^4=81

3^5=243

......

I could have also did negative integer powers, but this is all I really need to convince you that log_3(28) is between 3 and 4.

log_3(28) means the value x such that 3^x=28.

Since 28 is between 27 and 81 in my list above, that means 3^x is between 3^3 and 3^4. This means that x is a value between 3 and 4.

8 0
3 years ago
Please help
zheka24 [161]
The answer is C

O,p,m,q,n
3 0
2 years ago
Inverse of f(x)=-5x+15
Otrada [13]

f(x) = -5x - 15


Let y = f(x)


y = -5x - 15


Switch the x and y places, and solve for y:


x = -5y - 15


-5y = x + 15


y = (x + 15)/-5


y = -(x/5) - 3


So the inverse of : f(x) = -5x - 15 is


-x/5 - 3

5 0
4 years ago
Emmett gathered some data to compare the monthly cost of renting a one-bedroom apartment in Dallas and Austin. The data collecte
Goryan [66]

Answer:

The correct options are;

a) The city's data has the higher median monthly apartment cost of the two cities by $155

b) The city's data had the greater variability among monthly apartment costs because the standard deviation was $49.13 more than that of the other set of data

Step-by-step explanation:

The given data for the cost of renting a one-bedroom apartment in Dallas is presented as follows;

$994, $1,322, $1,075, $1,189, $1,172, $1,465, $1,215, $930, $1,090, $1,288

Which can be arranged in increasing order and analyzed to find the interquartile range, mean and standard deviation using Microsoft Excel as follows;

$930, $994, $1,075, $1,090, $1,172, $1,189, $1,215, $1,288, $1,322, and $ 1,465

The first quartile, Q₁ = $1,054.75

The third quartile, Q₃ = $1,296.5

The interquartile range = Q₃ - Q₁ = $241.75

The median = $1,180.5

The average monthly cost = $1,174

The standard deviation of the sample = $159.9597

The given data for the cost of renting a one-bedroom apartment in Austin is presented in increasing order using Microsoft Excel as follows;

$900, $950, $1,100, $1,250, $1,296, $1,375, $1,389, $1,400, $1,450, $1,495

The interquartile range, mean and standard deviation are found using Microsoft Excel as follows;

The first quartile, Q₁ = $1,062.5

The third quartile, Q₃ = $1,412.5

The interquartile range = Q₃ - Q₁ = $1,412.5 - $1,062.5 = $350

The median = $1,335.5

The average monthly cost = $1,260.5

The standard deviation of the sample = $209.0945

The difference in the median cost of the two cities is $1,335.5 - $1,180.5 = $155

Therefore, the Austin's city data has the higher median monthly apartment cost of the two cities by $155

b) The difference in the sample standard deviation of the two cities is $209.0945 - $159.9597 = $49.13476

Therefore, the Austin city data had the greater variability among monthly apartment costs because the standard deviation was $49.13 more than that of the other set of data.

7 0
3 years ago
Read 2 more answers
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