Question

The addition of 250.0 J to 30.0 g of copper initially at 22.0°C will change its temperature to what final value? (Specific heat of Cu= 0.387 J/g °C

Answer 1

Answer:

Final temperature = $43.53^{\circ} C$

Explanation:

Given that,

Heat added, Q = 250 J

Mass, m = 30 g

Initial temperature, T₁ = 22°C

The Specific heat of Cu= 0.387 J/g °C

We know that, heat added due to the change in temperature is given by :

$Q=mc\Delta T\\\\Q=mc(T_2-T_1)\\\\\dfrac{Q}{mc}=(T_2-T_1)\\\\T_2=\dfrac{Q}{mc}+T_1$

Put all the values,

$T_2=\dfrac{250}{30\times 0.387}+22\\\\=43.53^{\circ} C$

So, the final temperature is equal to $43.53^{\circ} C$.