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Propane has a molecular formula C3H8.
It is of the form CnH2n+2.
where n = number of C atoms. In present case n = 3.
Each carbon atom in propane is sp3 hydribized. Thus, there are 4 hydrid orbital associated with each carbon atom
The central C atom is sigma bonded to two other carbon atoms and two hydrogen atoms.
Such, sp3 hydridized orbitals are spacial orientated at an angle of
, in order to minimize repulsion between the electrons.
Hence, the c—c—c bond angle in propane, c3h8, is closest to
It is of the form CnH2n+2.
where n = number of C atoms. In present case n = 3.
Each carbon atom in propane is sp3 hydribized. Thus, there are 4 hydrid orbital associated with each carbon atom
The central C atom is sigma bonded to two other carbon atoms and two hydrogen atoms.
Such, sp3 hydridized orbitals are spacial orientated at an angle of
Hence, the c—c—c bond angle in propane, c3h8, is closest to
Answer:
14.533 grams of solid precipitate of mercury(II) dichromate will form.
Explanation:
Moles of mercury(II) acetate =
Moles of sodium dichromate =
According to reaction , 1 mole of sodium dichromate reacts with 1 mole of mercury(II) acetate , then 0.045906 moles of sodium dichromate will recat with :
of mercury(II) acetate
This means that mercury(II) acetate is present in an excess amount and sodium dichromate is present in limiting amount.So, amount of precipitate will depend upon moles of sodium dichromate.
According to reaction , 1 mole of sodium dichromate gives 1 mole of mercury(II) dichromate , then 0.045906 moles of sodium dichromate will give :
of mercury(II) dichromate
Mass of 0.045906 moles of mercury(II) dichromate:
0.045906 mol × 316.59 g/mol = 14.533 g
14.533 grams of solid precipitate of mercury(II) dichromate will form.