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zepelin [54]
1 year ago
8

Please answer this.A) ____ N2 + ____ H2 → ____ NH3B) ____ KClO3 → ____ KCl + ____ O2C) ____ NaCl + ____ F2 → ____ NaF + ____ Cl2

D) ____ C8H18 + ____ O2 → ____ CO2 + ____ H2OE) ____ FeCl3 + ____ NaOH → ____ Fe(OH)3 + ____NaClF) ____ P + ____O2 → ____P2O5G) ____ Na + ____ H2O → ____ NaOH + ____H2H) ____ H2SO4 + ____ Ba(NO3)2 → ____ HNO3 + ____ BaSO4How many decomposition reactions are there in the set of reactions above?

Chemistry
1 answer:
Lady_Fox [76]1 year ago
8 0

1) Decomposition reactions. In this type of reaction, a compound is broken down into simpler compounds.

AB\rightarrow A+B

Option B is a decomposition reaction

B) ____ KClO3 → ____ KCl + ____ O2

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Carbon dioxide, water vapor, and oxygen pass through ---------------
Lelechka [254]
The answer is B) stomata.
5 0
2 years ago
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A sample of an ionic compound containing iron and chlorine is analyzed and found to have a molar mass of 126.8 g/mol. what is th
julsineya [31]
Answer is: <span>the charge of the iron in this compound is +2.
Atomic mass of iron is 55,8 g/mol.
Atomic mass of chlorine is 35,5 g/mol.
If compound is FeCl, molar mass would be 55,8 </span>g/mol + 35,5 g/mol = 91,3 g/mo, that is not correct.
If compound is FeCl₂, malar mass of compound would be:
55,8 g/mol + 2·35,5 g/mol = 126,8 g/mol, that is correct.
Oxaidation number of chlorine is -1.
5 0
2 years ago
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6. Calculate the molarity if 35.0 grams of KBr are dissolved in 700. ml?
olga55 [171]

Answer:

To calculate molarity, divide the number of moles of solute by the volume of the solution in liters. If you don't know the number of moles of solute but you know the mass, start by finding the molar mass of the solute, which is equal to all of the molar masses of each element in the solution added together.

Explanation:

try starting with 35.0 and dived it by the volume

8 0
2 years ago
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How many moles are in 2.12g Cr2O3
ohaa [14]

Answer:

0.01395mol Cr2O3

Explanation:

the molar mass of Cr2O3 is 151.9904 g/mol

2.12g Cr2O3 x 1 mol/151.9904g = 0.01395mol Cr2O3

4 0
2 years ago
Consider the elements: Na, Mg, Al, Si, P.
Olegator [25]

Answer:

The elements mentioned in the series are Na, Mg, Al, Si, and P. It can be seen that all these elements are located in the same period. The atomic number of the mentioned elements are Na-11, Mg-12, Al-13, Si-14, and P-15.

a) There will be an increase in the ionization energy with the increase in the element's atomic number across a period. More energy is needed to withdraw an electron from a completely occupied shell in comparison to an incompletely occupied shell.

The atomic number of Na is 11. When one electron is withdrawn from Na, it gets converted into the inert gas configuration of Ne. Thus, it will require more energy to withdraw the second electron from Na. Hence, Na exhibits the lowest second ionization energy.

b) Across the period, with an increase in the element's atomic number, the atomic radii reduces from left to right. Thus, P exhibits the smallest atomic radius.

c) The metallic nature of the elements reduces from left to right across a period in the periodic table. Thus, P is the least metallic element.

d) Diamagnetic signifies towards the element that exhibits pair electrons in its sub-shells. The electronic configuration of Mg is,

1s2 2s2 2p6 3s2

In Mg, no unpaired electrons are present, while all the remaining elements mentioned exhibit unpaired electrons in their valence shell. Thus, Mg is the diamagnetic element.

8 0
3 years ago
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