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3 years ago

Hiii please help me for balancing chemical equations:

Chemistry

2 answers:

Amanda [17]3 years ago

8 0

Answer:

2KI +Cl₂ → 2KCl +I₂

Explanation:

Potassium ion: K+

Iodide ion: I-

Thus, potassium iodide is KI.

Chlorine exist as a diatomic molecule thus it is written as Cl₂.

Chloride ion: Cl-

Thus, potassium chloride is KCl.

Iodine also exist as a diatomic molecule, thus it is written as I₂.

Write an unbalanced equation:

KI +Cl₂ → KCl +I₂

Now balance by ensuring the number of atoms of each element on each side is the same.

K: 1 ×2= 2

I: 1 ×2= 2

Cl₂: 2

K: 1 ×2= 2

I: 2

Cl: 1 ×2= 2

Thus, the balanced equation is:

2KI +Cl₂ → 2KCl +I₂

Zarrin [17]3 years ago

7 0

Answer:

KI + Cl2 = KCl + I2

Explanation:

hope this helps!!!

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What does homogeneous and herogeneous mean?

serious [3.7K]

Homogeneous:

denoting a process involving substances in the same phase (solid, liquid, or gaseous).

Herogeneous:

of or denoting a process involving substances in different phases (solid, liquid, or gaseous).

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3 years ago

How many atoms are there in 15.0 grams of Sulfur (S)?

aev [14]

Answer:

Explanation:

Mol x Avogadro's number

Mol : mass / molar mass

Avogadro's no: 6.02E+23

6 0

2 years ago

A 2.20 mol sample of NO 2 ( g ) is added to a 3.50 L vessel and heated to 500 K. N 2 O 4 ( g ) − ⇀ ↽ − 2 NO 2 ( g ) K c = 0.513

igor_vitrenko [27]

Answer:

[NO₂] = 0.434 M

[N₂O₄] = 0.0971 M

Explanation:

The equilibrum is: N₂O₄(g) ⇆ 2NO₂ (g)

1 moles of nitrogen (IV) oxide is in equilibrium with 2 moles of nitrogen dioxide.

Initally we only have 2.20 moles of NO₂. So let's write the equilibrium again:

2NO₂ (g) ⇆ N₂O₄(g)

Initially 2.20 mol -

React x x/2

X amount has reacted, and the half has been formed, according to stoichiometry.

Eq (2.20-x) / 3.50L (x/2)/ 3.50L

We divide by the volume because we need molar concentrations. Let's make the Kc's expression:

Kc = [N₂O₄] / [NO₂]²

0.513 = ((x/2)/ 3.50L) / [(2.20-x) / 3.50L]

0.513 = ((x/2)/ 3.50L) / [(2.20-x)² / 3.50L²]

0.513 = ((x/2)/ 3.50L) / [2.20-x)² / 3.50L²]

0.513 = ((x/2)/ 3.50L) / (4.84 - 4.40x + x²) / 12.25)

0.513 / 12.25 (4.84 - 4.40x + x²) = x/2 / 3.50

0.203 - 0.184x + 0.0419x² = x/2 / 3.50

3.50(0.203 - 0.184x + 0.0419x²) = x/2

7 (0.203 - 0.184x + 0.0419x²) - x = 0

1.421 - 2.288x + 0.2933x² = 0 → Quadratic formula

a = 0.2933 ; b = -2.288 ; c = 1.421

(-b +- √(b²-4ac)) / (2a)

x₁ = 7.12

x₂ = 0.68 → We consider this value, so we can have a (+) concentration.

Concentrations in the equilibrium are:

[NO₂] = (2.20-0.68) / 3.50 = 0.434 M

[N₂O₄] = (0.68/2) / 3.50 = 0.0971 M

8 0

2 years ago

Lithium diorganocopper (Gilman) reagents are prepared by treatment of an organolithium compound with copper(I) iodide. Decide wh

Ann [662]

Answer:

See explanation and image attached

Explanation:

The Gilman reagent is a lithium and copper (diorganocopper) reagent with a general formula R2CuLi. R is an alkyl or aryl group.

They are useful in the synthesis of alkanes because they react with organic halides to replace the halide group with an R group.

In this particular instance, we intend to synthesize propylcyclohexane. The structure of the lithium diorganocopper (Gilman) reagent required is shown in the image attached to this answer.

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2 years ago

How many bonds would be needed when bonding 2 atoms of nitrogen to achieve a full octet for both atoms?

andriy [413]

Answer:

3 bonds are needed.

Explanation:

The electrons that are involved in chemical bonding are those in the outer shell of the highest energy level of the atom. The electron configuration of nitrogen (N) is 1s²2s²2p³. That means thy at each nitrogen atom has 5 valence electrons: 2 electrons in the 2s orbital and 3 electrons in the 2p orbital. To fullfil the octet, each nitrogen atom needs 3 electrons. So, they can share each other 3 electrons to form 3 simple bonds. Therefore, the nitrogen molecule (N₂) has 3 bonds involving 6 bonding electrons or a triple bond.

8 0

2 years ago