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4 years ago

Calculate how many moles of NH3 form when each quantity of reactant completely reacts according to the equation:

1 answer:

7 0

The balanced chemical reaction is:

3N2H4(l)→4NH3(g)+N2(g)

The amounts given for the N2H4 reactant will be the starting point for our calculations.

2.6mol N2H4 ( 4 mol NH3 / 3 mol N2H4 ) = 3.47 mol NH3

4.05mol N2H4 ( 4 mol NH3 / 3 mol N2H4 ) = 5.4 mol NH3

63.8g N2H4 ( 4 mol NH3 / 3 mol N2H4 ) = 85.07 mol NH3

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1. You have 4.0 g of NaCl. Calculate the number of moles of NaCl

Mumz [18]

Answer:

0.07mol

Explanation:

n=mass/molar mass

molar mass of NaCl=23+35.5
58.5g/mol
n=4/58.5
0.07mol

4 0

3 years ago

How would Lithium gain full valence levels

Lubov Fominskaja [6]

Answer:

In order to have a full outer shell atoms can GAIN or LOSE electrons. Atoms with very few VALENCE electrons, such as Lithium, would need to gain many electrons for a full shell so it is easier for them to LOSE electrons and become POSITIVE.

Explanation:

- I hope this helped!

8 0

3 years ago

Según la Organización Mundial de la Salud, el nitrato de plata ( densidad = 4.35 g/cc ) es una sustancia con propiedades cáustic

OlgaM077 [116]

Answer:

737.52 mL de agua

Explanation:

En este caso solo debes usar la expresión de molaridad de una solución la cual es:

M = moles / V

Donde:

V: Volumen de solución.

Como queremos saber la cantidad de agua, queremos saber en otras palabras cual es la cantidad de solvente que se utilizó para preparar los 800 mL de disolución.

Una disolución se prepara con un soluto y solvente. El soluto lo tenemos, que es el nitrato de plata. Con la expresión de arriba, calculamos los moles de soluto, y luego su masa. Posteriormente, calculamos el volumen con la densidad, y finalmente podremos calcular el solvente de esta forma:

V ste = Vsol - Vsto

Primero calcularemos los moles de soluto:

moles = M * V

moles = 2 * 0.800 = 1.6 moles

Con estos moles, se calcula la masa usando el peso molecular reportado que es 169.87 g/mol:

m = moles * PM

m = 1.6 * 169.87 = 271.792 g

Ahora usando el valor de la densidad, calcularemos el volumen de soluto empleado:

d = m/V

V = m/d

V = 271.792 / 4.35

V = 62.48 mL

Finalmente, la cantidad de agua necesaria es:

V agua = 800 - 62.48

V agua = 737.52 mL

8 0

3 years ago

How many grams of krypton gas will occupy 2.55 liters at 1.25 atm if it occupies 3.75 liters at 0.750 atm at 255 K

tatiyna

Answer:

There will be 94.7 grams of krypton gas

Explanation:

Step 1: Data given

at 255K and 0.750 atm the volume is 3.75 L

At 1.25 atm the volume is 2.55 L

Molar mass of krypton = 83.798 g/mol

Step 2: Calculate number of moles

p*V = n*R*T

with p = the pressure of the krypton gas = 0.750 atm

with V = the volume of the krypton gas = 3.75 L

with n = the number of moles = TO BE DETERMINED

with R = the gasconstant = 0.08206 L*atm/ mol * K

with T = the temperature = 255 K

n = R*T / p*V

n = (0.08206 * 255)/ (0.750 * 3.75)

n = 0.744 moles

Step 3: Calculate new number of moles

P1*V1 = P2*V2

P1*V1 = n1*R*T

P2*V2 = n2*R*T

(P1*V1)/R*T = (P2*V2)/n2*R*T

Since R and T do not change we can write as followed:

(P1*V1) = (P2*V2) /n2

n2 = (P2*V2) / (P1*V1)

n2 = (2.55 *1.25)/(0.75*3.75)

n2 = 1.13 moles

Step 4: Calculate mass of krypton gas

mass = Number of moles * Molar mass

mass of krypton gas = 1.13 moles * 83.798 g/mol = 94.69 grams ≈ 94.7 grams

There will be 94.7 grams of krypton gas

5 0

3 years ago

OMG PLS HELP ASAP!! It’s my FINAL and I need help. PLS!!

andrew-mc [135]

Answer:

25.)Intrusive rocks have a coarse grained texture. Extrusive Igneous Rocks: ... Quick cooling means that mineral crystals don't have much time to grow, so these rocks have a very fine-grained or even glassy texture. Hot gas bubbles are often trapped in the quenched lava, forming a bubbly, vesicular texture.

Explanation:

7 0

2 years ago