Calculate how many moles of NH3 form when each quantity of reactant completely reacts according to the equation:

1 answer:

7 0

The balanced chemical reaction is:

3N2H4(l)→4NH3(g)+N2(g)

The amounts given for the N2H4 reactant will be the starting point for our calculations.

2.6mol N2H4 ( 4 mol NH3 / 3 mol N2H4 ) = 3.47 mol NH3

4.05mol N2H4 ( 4 mol NH3 / 3 mol N2H4 ) = 5.4 mol NH3

63.8g N2H4 ( 4 mol NH3 / 3 mol N2H4 ) = 85.07 mol NH3

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One mole of acetyl chloride was mixed with one mole of dimethylamine. After the reaction is complete, what species can be found

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Answer:

N,N-dimethylacetamide is formed.

Explanation:

It is an example of a nucleophilic addition-elimination reaction. Here dimethylamine acts as a nucleophile.
In the first step, dimethyl amine gives nucleophilic addition reaction at carbonyl center of acetyl chloride.
In the second step, removal of Cl atoms occurs.
In the third step, deprotonation takes place from amino group to produce N,N-dimethylacetamide.
Full reaction mechanism has been shown below.