All categories

3 years ago

Will the solubility of CaSO4 in 0.10 Molar CaF2 be smaller than, larger than, or the same as in pure water?

Chemistry

1 answer:

Kay [80]3 years ago

3 0

Smaller than; less of it will dissolve before the solution is saturated

You might be interested in

Kyle is swinging at the playground. As he moves from the top of the swing to the bottom he will _____.

scoundrel [369]

Answer:

Neither

Explanation:

Kyle would gain potential energy and lose kinetic energy

8 0

3 years ago

Consider an electron placed in a region of space in which the electric potential spatially. The electron is placed at a point wh

loris [4]

Answer:

$1.33\cdot 10^7 m/s$

Explanation:

For a charged particle accelerated by an electric field, the kinetic energy gained by the particle is equal to the decrease in electric potential energy of the particle; therefore:

$K_f-K_i = -q\Delta V$

where

$K_f$ is the final kinetic energy

$K_i$ is the initial kinetic energy

q is the charge of the particle

$\Delta V$ is the potential difference

In this problem,

$q=-1.6\cdot 10^{-19}C$ is the charge of the electron

$\Delta V=-500 V-(-1000 V)=500 V$

The electron starts from rest, so its initial kinetic energy is

$K_i=0$

Therefore,

$K_f=-(-1.6\cdot 10^{-19})(500)=8\cdot 10^{-17}J$

We can write the final kinetic energy of the electron as

$K_f=\frac{1}{2}mv^2$

where

$m=9.11\cdot 10^{-31} kg$ is the electron mass

v is the final speed

And solving for v,

$v=\sqrt{\frac{2K_f}{m}}=\sqrt{\frac{2(8\cdot 10^{-17})}{9.11\cdot 10^{-31}}}=1.33\cdot 10^7 m/s$

5 0

3 years ago

How much heat energy, in kilojoules, is required to convert 72.0 gg of ice at −−18.0 ∘C∘C to water at 25.0 ∘C∘C ? Express your a

Ghella [55]

Answer: The enthalpy change is 34.3 kJ

Explanation:

The conversions involved in this process are :

$(1):H_2O(s)(-18^0C)\rightarrow H_2O(s)(0^0C)\\\\(2):H_2O(s)(0^0C)\rightarrow H_2O(l)(0^0C)\\\\(3):H_2O(l)(0^0C)\rightarrow H_2O(l)(25^0C)$

Now we have to calculate the enthalpy change.

$\Delta H=[m\times c_{s}\times (T_{final}-T_{initial})]+n\times \Delta H_{fusion}+[m\times c_{l}\times (T_{final}-T_{initial})]$

where,

$\Delta H$ = enthalpy change = ?

m = mass of water = 72.0 g

$c_{s}$ = specific heat of ice = $2.09J/g^0C$

$c_{l}$ = specific heat of liquid water = $4.184J/g^0C$

n = number of moles of water = $\frac{\text{Mass of water}}{\text{Molar mass of water}}=\frac{72.0g}{18g/mole}=4.00moles$

$\Delta H_{fusion}$ = enthalpy change for fusion = 6010 J/mole

Now put all the given values in the above expression, we get

$\Delta H=[72.0g\times 2.09J/g^0C\times (0-(-18)^0C]+4.00mole\times 6010J/mole+[72.0g\times 4.184J/g^)C\times (25-0)^0C]$ $\Delta H=34279.8J=34.3kJ$ (1 KJ = 1000 J)

Therefore, the enthalpy change is 34.3 kJ

5 0

3 years ago

How many secondary (2°) carbons are found in 5-ethyl-3,3,4-trimethylheptane??

Gelneren [198K]

5-Ethyl-3,3,4-trimethylheptane has 3 secondary carbon. A primary carbon written as 1° is a carbon that has one carbon atom attached to it. A secondary carbon written as 2° is a carbon attached to two other carbons, while a tertiary carbon written as 3° is a carbon attached to three other carbons.

6 0

4 years ago

Read 2 more answers

(Science)

AlladinOne [14]

Answer:

Explanation:

eons are divided into eras and eras are based on major events and can vary in time so eons can vary in time

8 0

3 years ago