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3 years ago

Explain the difference between commensalism,parasitism,and mutualism and give examples of each

1 answer:

6 0

Commercialism is when one benefits while the other gets no harm nor benefit.
Example: the Remora rides attached to bigger types of fish or shark and eat the remains of meals left behind from the organism they are attached to.

Parasitism is when benefits and the other is harmed.
Example: A tape worm feeds off the intestines and eat what the host eats, killing the host because they are deprived of nutrients.

Mutualism is when both benefit.
Example: when a bird is allowed to peck the food from a rhinos mouth to help the rhinos teeth and allows the birth food.

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When a gas is cooled the particles is moving fast or slowly

Sergeu [11.5K]

Answer:slowly

Explanation: when a gas is being cooled then its particles are gonna slowly stop moving to form a liquid

4 0

2 years ago

A gaseous system undergoes a change in temperature and volume. What is the entropy change for a particle in this system if the f

deff fn [24]

Explanation:

Entropy means the amount of randomness present within the molecules of the body of a substance.

Relation between entropy and microstate is as follows.

S = $K_{b} \times ln \Omega$

where, S = entropy

$K_{b}$ = Boltzmann constant

$\Omega$ = number of microstates

This equation only holds good when the system is neither losing or gaining energy. And, in the given situation we assume that the system is neither gaining or losing energy.

Also, let us assume that $\Omega$ = 1, and $\Omega'$ = 0.833

Therefore, change in entropy will be calculated as follows.

$\Delta S = K_{b} \times ln \Omega' - K_{b} \times ln \Omega$

= $1.38 \times 10^{-23} \times ln(0.833) - 1.38 \times 10^{-23} \times \times ln(1)$

= $1.38 \times 10^{-23} \times (-0.182)$

= $-0.251 \times 10^{-23}$

or, = $-2.51 \times 10^{-24}$

Thus, we can conclude that the entropy change for a particle in the given system is $-2.51 \times 10^{-24}$ J/K particle.

8 0

3 years ago

A certain substance X has a normal freezing point of -10.1 degree C and a molal freezing point depression constant K_f = 5.32 de

kirill115 [55]

Answer: $-15.4^00C$

Explanation:

$T^0_f-T_f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_f$ = boiling point of solution = ?

$T^o_f$ = boiling point of solvent (X) = $-10.1^oC$

$k_f$ = freezing point constant = $5.32^oC/kgmol$

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte like urea)

= mass of solute (urea) = 29.82 g

= mass of solvent (X) = 500.0 g

$M_2$ = molar mass of solute (urea) = 60 g/mol

Now put all the given values in the above formula, we get:

$(-10.1-(T_f))^oC=1\times (5.32^oC/m)\times \frac{(29.82g)\times 1000}{60\times (500.0g)}$

$T_f=-15.4^0C$

Therefore, the freezing point of solution is $-15.4^0C$

7 0

3 years ago

Why is air considered a mixture not a compound?

blondinia [14]

<span>The best reason I can think of for why we believe that air is a mixture is that freezing air slowly yields different liquids at different temperatures. Liquid nitrogen has a different boiling point than liquid oxygen. They also freeze at different temperatures. If air were only 1 compound, then air in its entirety would have a single boiling point and a single freezing point. </span>

8 0

3 years ago

In everyday speech the words precision and accuracy are often used interchangeably. When these terms are used in science are the

padilas [110]

Answer:

No, in science their meanings are not the same as their everyday meanings.

Explanation:

In Science, Precision and Accuracy are defined as,

Accuracy:

Accuracy is the value which is closest to the known or standard value.

Precision:

While, Precision is the value of closeness of two measured values to each other.

Example:

Let suppose in Chemistry Lab you weight an object as 50 g. While the actual weight of that object is 30 g. It means your reading is not accurate.

On second measurement you find that the object weight is 31 g. This time your reading is not precise.

3 0

3 years ago