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4 years ago

Explain the difference between commensalism,parasitism,and mutualism and give examples of each

1 answer:

6 0

Commercialism is when one benefits while the other gets no harm nor benefit.
Example: the Remora rides attached to bigger types of fish or shark and eat the remains of meals left behind from the organism they are attached to.

Parasitism is when benefits and the other is harmed.
Example: A tape worm feeds off the intestines and eat what the host eats, killing the host because they are deprived of nutrients.

Mutualism is when both benefit.
Example: when a bird is allowed to peck the food from a rhinos mouth to help the rhinos teeth and allows the birth food.

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If you burn 50.6 g of hydrogen and produce 452 g of water, how much oxygen reacted?

Svetllana [295]

Acc. to Law of Conservation of Mass
Mass of reactants=Mass of Products
Let mass of Oxygen be x.
So,
50.6+x=452
x=452-50.6
=401.4 g

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4 years ago

When the following equation is balanced, what is the coefficient for HBr?

deff fn [24]

D.) Balanced equation is Zn + 2HBr - - - > ZnBr2 + H2.

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4 years ago

Which two practices are examples of how people use science?

Anika [276]

B. Developing theories using many lines of evidence

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3 years ago

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Given 3.4 grams of x compound with a molar mass of 85 g and 4.2 grams of y compound with a molar mass of 48 g How much of compou

Ulleksa [173]

Answer:

$4.36~g~XY$

Explanation:

In this case, we can start with the reaction:

$2X + Y_2~->~2XY$

If we check the reaction, we will have 2 X and Y atoms on both sides. So, the reaction is balanced. Now, the problem give to us two amounts of reagents. Therefore, we have to find the limiting reagent. The first step then is to find the moles of each compound using the molar mass:

$3.4~g~X\frac{1~mol~X}{85~g~X}=0.04~mol~X$

$4.2~g~Y_2\frac{1~mol~Y_2}{48~g~Y_2}=0.0875~mol~Y_2$

Now, we can divide by the coefficient of each compound (given by the balanced reaction):

$\frac{0.04~mol~X}{1}=~0.04$

$\frac{0.0875~mol~Y_2}{2}=0.04375$

The smallest value is for "X", therefore this is our limiting reagent. Now, if we use the molar ratio between "X" and "XY" we can calculate the moles of XY, so:

$0.04~mol~X\frac{2~mol~XY}{2~mol~X}=0.04~mol~XY$

Finally, with the molar mass of "XY" we can calculate the grams. Now, we know that 1 mol X = 85 g X and 1 mol $Y_2$ = 48 g $Y_2$ (therefore 1 mol Y = 24 g Y). With this in mind the molar mass of XY would be 85+24 = 109 g/mol. With this in mind:

$0.04~mol~XY\frac{109~g~XY}{1~mol~XY}=4.36~g~XY$

I hope it helps!

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3 years ago

A solution containing aluminium ions reacts with a solution containing hydroxide ions to form a

Xelga [282]

Answer:

Explanation:

the answer is d white precipitate

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3 years ago

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