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oksano4ka [1.4K]
3 years ago
10

Please help, this is stem class!! Due in 30 minutes!!

Chemistry
2 answers:
7nadin3 [17]3 years ago
8 0

Answer: .....

Explanation:

Leto [7]3 years ago
8 0

answer it your self mate

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Hows everyone doing? tell me about your day in the comments thingy. mine aint going so great :/
GarryVolchara [31]

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Mine is doing good since I dont have any school today it makes it better. Im listening to scary stories on YT right now which always makes my day better so Im having a really good day today!

What about you? Why isn't your day doing so great?

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When are ions formed?
jek_recluse [69]
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4 years ago
Use the information below to answer the following questions.
Anni [7]

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3 0
4 years ago
A 30-0 g sample of water at 280 K is mixed with 50.0 g of water at 330 K. How would you calculate the final temperature of the m
aliya0001 [1]

Answer:

311.25k

Explanation:

The question assumes heat is not lost to the surroundings, therefore

heat emitted from hotter sample ( q_{\ lost} )= heat absorbed by the less hotter  sample( q_{\ gain} )

The relationship between heat (q), mass (m) and temperature (t) is q = mc\Delta t

where c is specific heat capacity, \Delta t temperature change.

\Delta t = t_{\ final} - t_{\ initial}

equating both heat emitted and absorb

-q_{\ lost} = q_{\ gain}

-m_{1}(t_{\ final} - t_{\ 1initial})=m_{2}(t_{\ final} - t_{\ 2initial})

where the values with subset 1 are the values of the hotter sample of water and the values with subset 2 are the values of the less hot sample of water.

C will cancel out since both are water and they have the same specific heat capacity.

so we have

-m_{1}(t_{\ final} - t_{\ 1initial})=m_{2}(t_{\ final} - t_{\ 2initial})

where m1 = 50g, t 1initial = 330, m2 = 30g, t2 initial = 280,t final (final temperature of the mixture) = ?

-50 * (t_{final} - 330) = 30 *  (t_{final} - 280)

-50t_{final} + 16500 = 30t_{final} - 8400

80t_{final} = 16500+8400

80t_{final} = 24900

t_{final} = 24900/80 = 311.25k

8 0
3 years ago
How many grams of moles are in 94.2 g of C02?
notsponge [240]

Answer:

Moles to grams carbon dioxide

1 mole is equal to 1 moles Carbon Dioxide, or 44.0095 grams.

Explanation:

Moles to grams carbon dioxide

1 mole is equal to 1 moles Carbon Dioxide, or 44.0095 grams.

5 0
3 years ago
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