Answer:
The answer to your question is V2 = 1244 L
Explanation:
Data
Temperature 1 = 11°C
Volume = 1.03 x 10³ L
Temperature 2 = 70°C
Volume 2 = ?
To solve this problem use the Charles' law
V1/ T1 = V2 / T2
-Solve for V2
V2 = V1T2 / T1
Process
1.- Convert temperature to °K
Temperature 1 = 11°C + 273 = 284°K
Temperature 2 = 70°C + 273 = 343°K
2.- Substitution
V2 = (1.03 x 10³)(343) / 284
3.- Simplification
V2 = 353290 / 284
4.- Result
V2 = 1244 L
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